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111848-67-0

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111848-67-0 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 111848-67-0 includes 9 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 6 digits, 1,1,1,8,4 and 8 respectively; the second part has 2 digits, 6 and 7 respectively.
Calculate Digit Verification of CAS Registry Number 111848-67:
(8*1)+(7*1)+(6*1)+(5*8)+(4*4)+(3*8)+(2*6)+(1*7)=120
120 % 10 = 0
So 111848-67-0 is a valid CAS Registry Number.

111848-67-0Relevant articles and documents

Hydrodealkoxylation reactions of silyl ligands at platinum: Reactivity of SiH3 and SiH2Me complexes

Mitzenheim, Cathérine,Braun, Thomas,Laubenstein, Reik,Braun, Beatrice,Herrmann, Roy

, p. 6394 - 6404 (2016/05/09)

The platinum(ii) complex [Pt(H)2(dcpe)] (1; dcpe = 1,2-bis(dicyclohexylphosphino)ethane) reacts with an excess of the dialkoxymethylsilanes (HSiMe(OR)2; R = Me, Et) to give the bis(silyl) complex [Pt(SiH2Me)2(dcpe)] (3) and trialkoxymethylsilanes by hydrodealkoxylation reactions. These rearrangements of the silyl ligands involve Si-O bond activations. The exchange of the alkoxy moieties against silicon-bound hydrogen atoms occurs stepwise. The intermediate complexes [Pt(H){SiMe(OEt)2}(dcpe)] (5), [Pt{SiMe(OEt)2}2(dcpe)] (6), [Pt{SiHMe(OEt)}2(dcpe)] (7) and [Pt{SiHMe(OMe)}2(dcpe)] (8) were detected. Treatment of the complex 1 with an excess of dichloromethylsilane yields the bis(silyl) complex [Pt(SiMeCl2)2(dcpe)] (9). The hydrido silyl complex [Pt(H)(SiMeCl2)(dcpe)] (10) was identified as an intermediate. The reactions of the complexes [Pt(SiH3)2(dcpe)] (2) and [Pt(SiH2Me)2(dcpe)] (3) with iodomethane lead to a transfer of the SiH3 and SiH2Me ligands. Methylsilane and dimethylsilane, respectively, as well as the platinum diiodo complex [Pt(I)2(dcpe)] (11) were identified as main products.

platinum(0). Reactions with Alkyl, (Trimethylsilyl)methyl, Aryl, Benzyl, and Alkynyl Carbon-Hydrogen Bonds

Hackett, Marifaith,Whitesides, George M.

, p. 1449 - 1462 (2007/10/02)

cis-Hydridoneopentylplatinum(II) (1) reductively eliminates neopentane and generates platinum(0) (2).This bent bis(phosphine)platinum(0) complex was not observed directly; its intermediac

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