7932 J. Phys. Chem. A, Vol. 101, No. 43, 1997
Mao and Bakac
+
•
UO2+ + C10H8
(6a)
(6b)
SCHEME 1
*UO22+ + C10H8
2+
(UO2 • • •C10H8)*
UO22+ + C10H8
2+
Even though the oxidation of organic substrates by *UO2
is fairly common,1,2,5,7,23-25 such reactions typically take place
by hydrogen atom abstraction or initial addition to multiple
bonds. To our knowledge, an outer-sphere electron transfer
2+
between *UO2 and a hydrocarbon has not been reported
previously. As expected, the rate constant k6a (∼0.3 × k6 ∼ 7
× 108 M-1 s-1) is somewhat smaller than those for the more
easily oxidizable ABTS2- (1.3 × 109 M-1 s-1) and 1,4-
dimethoxybenzene (2.3 × 109 M-1 s-1). A more quantitative
comparison would be difficult to make, because all three
reactions approach the diffusion-controlled limit. The data do
suggest, however, that the proportion of electron transfer to
exciplex formation would become even greater for the larger,
more strongly reducing26 polynuclear aromatics.
2+
(C16H10•+) with k ) 1.0 × 1010 M-1 s-1 34
,
and Euaq reacts
with C10H8•+ with k ) 3.9 × 109 M-1 s-1 35
.
The driving force26
for reaction 10 is smaller than that for the reaction of C10H8
with Eu2+, and the rate constant k10 on the order of 108-109
M-1 s-1 appears reasonable.
•+
Naphthols are typical products of oxidation of naphthalene
in aqueous solvents.10,16,27,28 In the commonly accepted mech-
Table 3 compares the products of oxidation of naphthalene
in several systems. Naphthols are produced in most of the
reactions, but the yield and distribution of all the products vary
widely, presumably because of the high reactivity of intermedi-
ates involved. The Fenton reaction,27 which involves HO•
radicals, and Udenfriend’s system,28 which is believed to utilize
iron-oxo and -peroxo species, yield a large number of products.
γ-Radiolysis in the presence of Fe(CN)63- produces naphthols
anism of eqs 7-9, the OH adduct is produced either directly
•+
by addition of HO• to naphthalene or by hydrolysis of C10H8
The intermediates produced by one-electron oxidation (C10H8
.
•+
)
and in Fenton-type reactions (C10H8(OH•)) are thus related by
acid-base chemistry of eq 8. Further oxidation of C10H8(OH)•
then yields a mixture of naphthols.29,30 In the *UO22+-initiated
2+
oxidation, the oxidant in eq 9 is either O2 or UO2
. No
in a scheme6 that involves rapid oxidation of C10H8(HO•)
products were observed in the absence of O2, which may mean
that it plays a role in eq 9. Another possibility is that O2 helps
the reaction only indirectly by keeping the concentration of
3-
adducts by Fe(CN)6
.
A PdCl2-based system16 produces
2-formylcinnamaldehyde and 1-naphthol. The latter is oxidized
further to 1,4-naphthoquinone. In the photochemical UO2
2+
UO2+ low,31 eq 3, thus slowing down the back electron transfer
/
2+
O2 system described here, 2-formylcinnamaldehyde is the major
product, Scheme 1. The yields are low, but the results are
encouraging in that electron transfer is a significant pathway in
the quenching process. We expect the yields of products,
especially naphthols, to increase in the presence of sacrificial
of eq 10. In this scenario, the oxidant in eq 9 is UO2
.
C10H8 + HO• f C10H8(OH)•
(7)
(8)
C10H8•+ + H2O a C10H8(OH)• + H+
+
oxidants, which would rapidly remove UO2 and thus prevent
C10H8(OH)• 9Ox8 C10H7(OH)
(9)
the back electron transfer of eq 10.
UO2+ + C10H8•+ f UO22+ + C10H8
(10)
Conclusions
The photochemical oxidation of naphthalene by UO22+/O2
yields 2-formylcinnamaldehyde as a major product. Minor
amounts of 1- and 2-naphthols were also found. The reaction
takes place by one-electron oxidation of naphthalene, followed
by further reactions of C10H8•+. The quantum yield for the
The formation of 2-formylcinnamaldehyde as a major product
shows that the ring cleavage is an important process. As shown
in Scheme 1, this pathway probably starts with deprotonation
of the strongly acidic32 radical cation followed by the reaction
with O2 and formation of the peroxyl radicals. The radical
center may couple with the neighboring ring carbon to produce
a transient cyclic peroxide,13,15 although there is no direct
evidence for such intermediates.28 Irrespective of whether the
cyclic peroxide is involved or not, further reaction requires a
hydrogen source (possibly solvent) or one-electron reduction
(possibly by UO2+) followed by protonation to yield the
dialdehyde. A similar mechanism has been proposed in some
other oxidations of naphthalene.28,33 The UO2+, produced in
reaction 6a, reacts either with O2 to regenerate UO22+ (eq 3) or
in a back electron transfer of eq 10.
Despite the fact that ∼30% of quenching in eq 6 takes place
by electron transfer, the total quantum yield of all the products
is less than 1%. The most apparent reason is the back electron
transfer of eq 10, which restores the reactants in their ground
states. On the basis of the known precedents, the rate constant
k10 is expected to be large and probably close to diffusion
control. For example, ferrocene reduces pyrene radical cations
•+
formation of C10H8 in the quenching process is 0.3, but the
overall quantum yield for the formation of products is <0.01,
•+
suggesting that most of C10H8 is re-reduced to naphthalene
+
by back electron transfer with UO2
.
Acknowledgment. We are grateful to Dr. J. H. Espenson
for helpful discussions and to Mr. J. Jacob for his assistance
with some experiments. This work was supported by the U.S.
Department of Energy, Office of Basic Energy Science, Division
of Chemical Sciences, under Contract W-7405-Eng-82. An
Ames Laboratory Directed Research and Development Grant
is gratefully acknowledged.
References and Notes
(1) Burrows, H. D.; Kemp, T. J. Chem. Soc. ReV. 1974, 3, 139.
(2) Balzani, V.; Bolletta, F.; Gandolfi, M. T.; Maestri, M. Top. Curr.
Chem. 1978, 75, 1-64.
(3) Matsushima, R. J. Am. Chem. Soc. 1972, 94, 6010.