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Posaconazole hydrate

Base Information Edit
  • Chemical Name:Posaconazole hydrate
  • CAS No.:1198769-38-8
  • Molecular Formula:C37H44F2N8O5
  • Molecular Weight:718.8
  • Hs Code.:
  • ChEMBL ID:CHEMBL4303216
  • Mol file:1198769-38-8.mol
Posaconazole hydrate

Synonyms:4-(p-(4-(p-(((3R,5R)-5-(2,4-difluorophenyl)tetrahydro-5-(1H-1,2,4-triazol-1-ylmethyl)-3-furyl)methoxy)phenyl)-1-piperazinyl)phenyl)-1-((1S,2S)-1-ethyl-2-hydroxypropyl)-delta(sup 2)-1,2,4-triazolin-5-one;Noxafil;posaconazole;posaconazole hydrate;SCH 56592;SCH-56592

Suppliers and Price of Posaconazole hydrate
Supply Marketing:Edit
Business phase:
The product has achieved commercial mass production*data from LookChem market partment
Manufacturers and distributors:
  • Manufacture/Brand
  • Chemicals and raw materials
  • Packaging
  • price
  • DC Chemicals
  • Posaconazolehydrate >98%
  • 100 mg
  • $ 680.00
  • DC Chemicals
  • Posaconazolehydrate >98%
  • 10 mg
  • $ 96.00
  • Crysdot
  • Posaconazolehydrate 98+%
  • 10mg
  • $ 84.00
  • Crysdot
  • Posaconazolehydrate 98+%
  • 5mg
  • $ 55.00
  • Biorbyt Ltd
  • Posaconazole hydrate
  • 100 mg
  • $ 1030.20
  • Biorbyt Ltd
  • Posaconazole hydrate
  • 50 mg
  • $ 593.30
  • Biorbyt Ltd
  • Posaconazole hydrate
  • 10 mg
  • $ 268.60
  • ApexBio Technology
  • Posaconazolehydrate
  • 10mg
  • $ 189.00
  • ApexBio Technology
  • Posaconazolehydrate
  • 5mg
  • $ 125.00
Total 3 raw suppliers
Chemical Property of Posaconazole hydrate Edit
Chemical Property:
  • Hydrogen Bond Donor Count:2
  • Hydrogen Bond Acceptor Count:12
  • Rotatable Bond Count:12
  • Exact Mass:718.34027286
  • Heavy Atom Count:52
  • Complexity:1170
Purity/Quality:

>98% *data from raw suppliers

Posaconazolehydrate >98% *data from reagent suppliers

Safty Information:
  • Pictogram(s):  
  • Hazard Codes: 
MSDS Files:
Useful:
  • Canonical SMILES:CCC(C(C)O)N1C(=O)N(C=N1)C2=CC=C(C=C2)N3CCN(CC3)C4=CC=C(C=C4)OCC5CC(OC5)(CN6C=NC=N6)C7=C(C=C(C=C7)F)F.O
  • Isomeric SMILES:CC[C@@H]([C@H](C)O)N1C(=O)N(C=N1)C2=CC=C(C=C2)N3CCN(CC3)C4=CC=C(C=C4)OC[C@H]5C[C@](OC5)(CN6C=NC=N6)C7=C(C=C(C=C7)F)F.O
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