1H-Tetrazole, 1-methyl-5-((3-((5-methyl-1,3,4-oxadiazol-2-yl)thio)propyl)thio)-

Base Information

Chemical Name:1H-Tetrazole, 1-methyl-5-((3-((5-methyl-1,3,4-oxadiazol-2-yl)thio)propyl)thio)-
CAS No.:80086-85-7
Molecular Formula:C₈H₁₂N₆OS₂
Molecular Weight:272.355
Hs Code.:
DSSTox Substance ID:DTXSID20230069
Wikidata:Q83110466

Synonyms:80086-85-7;1-Methyl-5-((3-((5-methyl-1,3,4-oxadiazol-2-yl)thio)propyl)thio)-1H-tetrazole;1H-Tetrazole, 1-methyl-5-((3-((5-methyl-1,3,4-oxadiazol-2-yl)thio)propyl)thio)-;C8H12N6OS2;SCHEMBL10975147;DTXSID20230069;C8-H12-N6-O-S2;LS-149171

Suppliers and Price of 1H-Tetrazole, 1-methyl-5-((3-((5-methyl-1,3,4-oxadiazol-2-yl)thio)propyl)thio)-

Supply Marketing:

Business phase:: The product has achieved commercial mass production^*data from LookChem market partment

Manufacturers and distributors:

Manufacture/Brand
Chemicals and raw materials
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price

Total 1 raw suppliers

Chemical Property of 1H-Tetrazole, 1-methyl-5-((3-((5-methyl-1,3,4-oxadiazol-2-yl)thio)propyl)thio)-

Chemical Property:

Vapor Pressure:1.05E-09mmHg at 25°C
Boiling Point:488.8°Cat760mmHg
Flash Point:249.4°C
Density:1.57g/cm³
XLogP3:1.5
Hydrogen Bond Donor Count:0
Hydrogen Bond Acceptor Count:8
Rotatable Bond Count:6
Exact Mass:272.05140137
Heavy Atom Count:17
Complexity:236

Purity/Quality:: 85.0-99.8% ^*data from raw suppliers

Safty Information:

Pictogram(s):
Hazard Codes:

MSDS Files:: SDS file from LookChem

Useful:

Canonical SMILES:CC1=NN=C(O1)SCCCSC2=NN=NN2C

Technology Process of 1H-Tetrazole, 1-methyl-5-((3-((5-methyl-1,3,4-oxadiazol-2-yl)thio)propyl)thio)-

There total 1 articles about 1H-Tetrazole, 1-methyl-5-((3-((5-methyl-1,3,4-oxadiazol-2-yl)thio)propyl)thio)- which guide to synthetic route it. The literature collected by LookChem mainly comes from the sharing of users and the free literature resources found by Internet computing technology. We keep the original model of the professional version of literature to make it easier and faster for users to retrieve and use. At the same time, we analyze and calculate the most feasible synthesis route with the highest yield for your reference as below:

synthetic route:

Reference yield: