Lidocaine-d10 N-Oxide

Base Information

Chemical Name:Lidocaine-d10 N-Oxide
CAS No.:851528-10-4
Molecular Formula:C₁₄H₂₂N₂O₂
Molecular Weight:260.261
Hs Code.:
DSSTox Substance ID:DTXSID60461335
Wikidata:Q82285627
Mol file:851528-10-4.mol

Synonyms:Lidocaine-d10 N-Oxide;851528-10-4;1,1,2,2,2-pentadeuterio-N-[2-(2,6-dimethylanilino)-2-oxoethyl]-N-(1,1,2,2,2-pentadeuterioethyl)ethanamine oxide;HY-B0185S;DTXSID60461335;CS-0200969

Suppliers and Price of Lidocaine-d10 N-Oxide

Supply Marketing:

Business phase:: The product has achieved commercial mass production^*data from LookChem market partment

Manufacturers and distributors:

Manufacture/Brand
Chemicals and raw materials
Packaging
price

Usbiological
Lidocaine-d10 N-Oxide
2.5mg
$ 460.00

TRC
Lidocaine-d10N-Oxide
25mg
$ 1190.00

TRC
Lidocaine-d10N-Oxide
2.5mg
$ 150.00

Total 0 raw suppliers

Chemical Property of Lidocaine-d10 N-Oxide

Chemical Property:

Melting Point:125-128°C
PSA：62.02000
LogP:3.26670
Storage Temp.:-20?C Freezer
Solubility.:Chloroform (Slightly), Methanol (Slightly, Heated)
XLogP3:2.6
Hydrogen Bond Donor Count:1
Hydrogen Bond Acceptor Count:2
Rotatable Bond Count:5
Exact Mass:260.230895408
Heavy Atom Count:18
Complexity:267

Purity/Quality:: Lidocaine-d10 N-Oxide ^*data from reagent suppliers

Safty Information:

Pictogram(s):
Hazard Codes:

MSDS Files:: SDS file from LookChem

Useful:

Canonical SMILES:CC[N+](CC)(CC(=O)NC1=C(C=CC=C1C)C)[O-]
Isomeric SMILES:[2H]C([2H])([2H])C([2H])([2H])[N+](CC(=O)NC1=C(C=CC=C1C)C)(C([2H])([2H])C([2H])([2H])[2H])[O-]
Uses A novel labelled metabolite of Lidocaine (L397800).

Technology Process of Lidocaine-d10 N-Oxide

There total 1 articles about Lidocaine-d10 N-Oxide which guide to synthetic route it. The literature collected by LookChem mainly comes from the sharing of users and the free literature resources found by Internet computing technology. We keep the original model of the professional version of literature to make it easier and faster for users to retrieve and use. At the same time, we analyze and calculate the most feasible synthesis route with the highest yield for your reference as below:

synthetic route:

Reference yield: