Urea, 1-(2-fluoroethyl)-3-(4-methylcyclohexyl)-1-nitroso-

Base Information

Chemical Name:Urea, 1-(2-fluoroethyl)-3-(4-methylcyclohexyl)-1-nitroso-
CAS No.:51759-73-0
Molecular Formula:C10H18FN3O2
Molecular Weight:231.27
Hs Code.:
NSC Number:125649
DSSTox Substance ID:DTXSID10186682
Nikkaji Number:J54.442F,J87.728J
ChEMBL ID:CHEMBL13005,CHEMBL3250438
Mol file:51759-73-0.mol

Synonyms:33024-36-1;1-(2-Fluoroethyl)-3-(4-methylcyclohexyl)-1-nitrosourea;Urea, 1-(2-fluoroethyl)-3-(4-methylcyclohexyl)-1-nitroso-;Urea, N-(2-fluorophenyl)-N'-(4-methylcyclohexyl)-N-nitroso-;NSC 125649;NSC 125,649;NSC-125649;1-(2-Fluoroethyl)-3-(E)(4-methylcyclohexyl)-1-nitrosourea;Urea, 1-(2-fluoroethyl)-3-(4-methylcyclohexyl)-1-nitroso-, (E)-;CHEMBL13005;CHEMBL3250438;DTXSID10186682;NSC125649

Suppliers and Price of Urea, 1-(2-fluoroethyl)-3-(4-methylcyclohexyl)-1-nitroso-

Supply Marketing:

Business phase:: The product has achieved commercial mass production^*data from LookChem market partment

Manufacturers and distributors:

Manufacture/Brand
Chemicals and raw materials
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price

Total 3 raw suppliers

Chemical Property of Urea, 1-(2-fluoroethyl)-3-(4-methylcyclohexyl)-1-nitroso-

Chemical Property:

PKA:10.87±0.40(Predicted)
Density:1.27g/cm³
XLogP3:3.1
Hydrogen Bond Donor Count:1
Hydrogen Bond Acceptor Count:4
Rotatable Bond Count:3
Exact Mass:231.13830499
Heavy Atom Count:16
Complexity:242

Purity/Quality:: 99% ^*data from raw suppliers

Safty Information:

Pictogram(s):
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MSDS Files:

Useful:

Canonical SMILES:CC1CCC(CC1)NC(=O)N(CCF)N=O

Technology Process of Urea, 1-(2-fluoroethyl)-3-(4-methylcyclohexyl)-1-nitroso-

There total 1 articles about Urea, 1-(2-fluoroethyl)-3-(4-methylcyclohexyl)-1-nitroso- which guide to synthetic route it. The literature collected by LookChem mainly comes from the sharing of users and the free literature resources found by Internet computing technology. We keep the original model of the professional version of literature to make it easier and faster for users to retrieve and use. At the same time, we analyze and calculate the most feasible synthesis route with the highest yield for your reference as below:

synthetic route:

Reference yield: