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Anthra(1,9-bc)thiopyran-7(2H)-one, 4(5 or 6)-bromo-9-chloro-2-(3-chloro-10-oxo-9(10H)-anthracenylidene)-, 3-oxide

Base Information
  • Chemical Name:Anthra(1,9-bc)thiopyran-7(2H)-one, 4(5 or 6)-bromo-9-chloro-2-(3-chloro-10-oxo-9(10H)-anthracenylidene)-, 3-oxide
  • CAS No.:72275-96-8
  • Molecular Formula:C42H25N7Na4O13S4
  • Molecular Weight:1055.91
  • Hs Code.:
  • European Community (EC) Number:276-561-2
Anthra(1,9-bc)thiopyran-7(2H)-one, 4(5 or 6)-bromo-9-chloro-2-(3-chloro-10-oxo-9(10H)-anthracenylidene)-, 3-oxide

Synonyms:EINECS 276-561-2;72275-96-8;Anthra(1,9-bc)thiopyran-7(2H)-one, 4(5 or 6)-bromo-9-chloro-2-(3-chloro-10-oxo-9(10H)-anthracenylidene)-, 3-oxide;Anthra[1,9-bc]thiopyran-7(2H)-one, 4(5 or 6)-bromo-9-chloro-2-(3-chloro-10-oxo-9(10H)-anthracenylidene)-, 3-oxide;4(5Or6)-bromo-9-chloro-2-(3-chloro-10-oxo-9(10H)-anthrylidene)anthra(1,9-bc)thiopyran-7(2H)-one;4(5or6)-bromo-9-chloro-2-(3-chloro-10-oxo-9(10H)-anthrylidene)anthra[1,9-bc]thiopyran-7(2H)-one;C30H13BrCl2O3S;C30-H13-Br-Cl2-O3-S;Anthra[1,9-bc]thiopyran-7(2H)-one, 4(5 or 6)-bromo-9-chloro-2-(3-chloro-10-oxo-9(10H)-anthracenylidene)-

Suppliers and Price of Anthra(1,9-bc)thiopyran-7(2H)-one, 4(5 or 6)-bromo-9-chloro-2-(3-chloro-10-oxo-9(10H)-anthracenylidene)-, 3-oxide
Supply Marketing:
Business phase:
The product has achieved commercial mass production*data from LookChem market partment
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Total 6 raw suppliers
Chemical Property of Anthra(1,9-bc)thiopyran-7(2H)-one, 4(5 or 6)-bromo-9-chloro-2-(3-chloro-10-oxo-9(10H)-anthracenylidene)-, 3-oxide
Chemical Property:
  • XLogP3:7
  • Hydrogen Bond Donor Count:0
  • Hydrogen Bond Acceptor Count:4
  • Rotatable Bond Count:0
  • Exact Mass:601.91458
  • Heavy Atom Count:37
  • Complexity:1100
Purity/Quality:

99% *data from raw suppliers

Safty Information:
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  • Hazard Codes: 
MSDS Files:

SDS file from LookChem

Useful:
  • Canonical SMILES:C1=CC=C2C(=C1)C(=C3C=C4C5=C(C=C(C=C5)Cl)C(=O)C6=C4C(=C(C=C6)Br)S3=O)C7=C(C2=O)C=C(C=C7)Cl
  • Isomeric SMILES:C1=CC=C2C(=C1)/C(=C\3/C=C4C5=C(C=C(C=C5)Cl)C(=O)C6=C4C(=C(C=C6)Br)S3=O)/C7=C(C2=O)C=C(C=C7)Cl
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