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[Pd(CH=CHPh)(μ-Br)(PMePh2)]2 is a chemical with a specific purpose. Lookchem provides you with multiple data and supplier information of this chemical.

1012327-73-9

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1012327-73-9 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 1012327-73-9 includes 10 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 7 digits, 1,0,1,2,3,2 and 7 respectively; the second part has 2 digits, 7 and 3 respectively.
Calculate Digit Verification of CAS Registry Number 1012327-73:
(9*1)+(8*0)+(7*1)+(6*2)+(5*3)+(4*2)+(3*7)+(2*7)+(1*3)=89
89 % 10 = 9
So 1012327-73-9 is a valid CAS Registry Number.

1012327-73-9Upstream product

1012327-73-9Downstream Products

1012327-73-9Relevant articles and documents

Reaction of trans-Pd(styryl)Br(PMePh2)2 with styryl bromide affording 1,4-diphenyIbutadiene. An unexpected homocoupling process induced by P-C reductive elimination

Wakioka, Masayuki,Nagao, Masato,Ozawa, Fumiyuki

, p. 602 - 608 (2008)

Reaction of (Z)-styryl bromide (1) with PhB(OH)2 in toluene at 80 °C for 1 h in the presence of Pd(PPh3)4 (1.5 mol %) and an aqueous solution of K2CO3 (3 equiv) affords (Z)-stilbene as the cross-coupling product in 99% yield. On the other hand, the same reaction of the (E)-isomer of 1 forms considerable amounts of homocoupling products (1,4-diphenylbutadiene (2, 22%) and biphenyl (27%)) in addition to the cross-coupling product ((E)-stilbene, 73%). The formation of 2 was examined by kinetic experiments using trans-Pd(CH=CHPh)Br(PMePh2)2 (3) as a model of the presumed intermediate. Complex 3 reacts with 1 at 50 °C for 5 h, giving 2 (91%) and irans-PdBr2(PMePh2) 2 (4, 92%), together with a small amount of Pd(η2- PhCH=CHPMePh2)Br(PMePh2) (5, 8%). The reaction rate shows firstorder dependence on the concentration of 3 and 5, respectively, but is independent of the concentration of 1. A novel homocoupling process induced by P-C reductive elimination from 3 giving 5 is proposed.

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