Welcome to LookChem.com Sign In|Join Free

CAS

  • or

105121-25-3

Post Buying Request

105121-25-3 Suppliers

Recommended suppliersmore

  • Product
  • FOB Price
  • Min.Order
  • Supply Ability
  • Supplier
  • Contact Supplier

105121-25-3 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 105121-25-3 includes 9 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 6 digits, 1,0,5,1,2 and 1 respectively; the second part has 2 digits, 2 and 5 respectively.
Calculate Digit Verification of CAS Registry Number 105121-25:
(8*1)+(7*0)+(6*5)+(5*1)+(4*2)+(3*1)+(2*2)+(1*5)=63
63 % 10 = 3
So 105121-25-3 is a valid CAS Registry Number.

105121-25-3Downstream Products

105121-25-3Relevant articles and documents

Cluster syntheses. 13. Chemistry of sulfidoruthenium carbonyl clusters. Synthesis and characterization of the new unsaturated clusters Ru4(CO)11-nLn(μ4-S)2 (n = 0-2, L = PMe2Ph)

Adams, Richard D.,Babin, James E.,Tasi, Miklos

, p. 4514 - 4519 (2008/10/08)

The compound Ru3(CO)9(μ3-CO)(μ3-S) (1) has been prepared by three methods: pyrolysis and photolysis of Ru3(CO)10(μ-SPh)(μ-H), in 89% and 80% yields, respectively, and the reaction of Ru3(CO)12 and ethylene sulfide in 67% yield. The compound Ru3(CO)9(μ3-S)2 (3) was prepared in 94% yield from the reaction of Ru3(CO)12 with an excess of ethylene sulfide. Compound 3 was also obtained from the reaction of 1 with ethylene sulfide in 97% yield. Compounds 1 and 3 react with hydrogen by loss of CO to form the compounds Ru3(CO)9(μ3-S)(μ-H)2 (2) and Ru3(CO)8(μ3-S)2(μ-H) 2 (4) in 92% and 48% yields, respectively. Compound 4 can be converted back into 3 by reaction with CO under 50 atm pressure in 94% yield. Compound 3 reacts with Ru(CO)5 in the presence of UV irradiation to form the tetraruthenium cluster Ru4(CO)9(μ-CO)2(μ4-S) 2 (5) in 90% yield. The reaction of 4 with PMe2Ph at 25°C yields the substitution products Ru4(CO)11-n(PMe2Ph)n(μ 4-S)2 (6, n = 1; 7, n = 2). The structure of 7 was established by a single-crystal X-ray diffraction analysis. Crystal data: space group, P21/n; a = 9.752 (2) A?; b = 20.471 (3) A?; c = 16.236 (2) A?; β = 93.04 (1)°; Z = 4; ρcalcd = 2.07 g/cm3. The structure was solved by direct methods and was refined (3843 reflections) to the final values of the residuals R = 0.027 and Rw = 0.031. The molecule consists of a square cluster of four ruthenium atoms with quadruply bridging sulfido ligands on the two square faces of the cluster. Two carbonyl ligands bridge adjacent edges of the square and produce a slight shortening of the two Ru-Ru bonds. The clusters of compounds 5 and 6 are believed to be structurally similar to 7. Compounds 5-7 contain 62 valence electrons and are therefore electron deficient by two electrons. They do, however, conform to the requirements of the polyhedral skeletal electron pair theory.

Post a RFQ

Enter 15 to 2000 letters.Word count: 0 letters

Attach files(File Format: Jpeg, Jpg, Gif, Png, PDF, PPT, Zip, Rar,Word or Excel Maximum File Size: 3MB)

1

What can I do for you?
Get Best Price

Get Best Price for 105121-25-3