Welcome to LookChem.com Sign In|Join Free
  • or
[Pd(P(C6H5)2CH2CH2Sn(CH3)2)2] is a chemical with a specific purpose. Lookchem provides you with multiple data and supplier information of this chemical.

134110-44-4

Post Buying Request

134110-44-4 Suppliers

Recommended suppliers

  • Product
  • FOB Price
  • Min.Order
  • Supply Ability
  • Supplier
  • Contact Supplier

134110-44-4 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 134110-44-4 includes 9 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 6 digits, 1,3,4,1,1 and 0 respectively; the second part has 2 digits, 4 and 4 respectively.
Calculate Digit Verification of CAS Registry Number 134110-44:
(8*1)+(7*3)+(6*4)+(5*1)+(4*1)+(3*0)+(2*4)+(1*4)=74
74 % 10 = 4
So 134110-44-4 is a valid CAS Registry Number.

134110-44-4Downstream Products

134110-44-4Relevant academic research and scientific papers

Ligand behaviour of P-functional organotin halides: Nickel(II), palladium(II), and platinum(II) complexes with me2(Cl)SnCH2CH2PPh2

Baumeister,Hartung,Krug,Merzweiler,Schulz,Wagner,Weichmann

, p. 2185 - 2195 (2008/10/08)

Me2(Cl)SnCH2CH2PPh2 (1) reacts with NiII, PdII, and PtII halides in molar ratio 2:1 forming the complexes [MX2{PPh2CH2CH2Sn(Cl)Me 2}2] (M = Ni, Pd, Pt; X = Cl, Br) (3-6, 9, 10) (7, 8: M = Ni; Br instead of Cl). The nickel complexes were isolated and characterized both as the planar (3, 5, 7) and the tetrahedral (4, 6, 8) isomer. Crystal structure analyses and NMR data indicate for the planar nikkel complexes 3, 5, 7 and [MCl2{PPh2CH2CH2Sn(Cl)Me 2}2] (9: M = Pd; 10: M = Pt) the existence of intra and intermolecular M-Hal...Sn bridges. In a ligand: metal molar ratio of 3:1 the complexes [M⊕Cl{PPh2CH2CH2Sn Cl2Me2}-(PPh2CH 2CH2Sn(Cl)Me2}2] (11: M = Pd; 12: M = Pt) are formed which represent intramolecular ion pairs. By dehalogenation of [PdCl2{PPh2CH2CH2Sn(Cl)Me 2}2] (9) with sodium amalgam and graphite potassium (C8K), respectively, the palladacycles cis-[Pd{PPh2CH2CH2SnMe2} 2] (13) and trans[Pd(Cl)PPh2CH2CH2SnMe2{PPh 2CH2CH2Sn(Cl)Me2}] (14) are formed. From the compounds 1, 3, 9, 11, and 12 the crystal structures are determined. All compounds are characterized by 1H, 31P, and 119Sn NMR spectroscopy.

Transition Metal Stannyl Complexes, 4. - Palladium and Platinum Complexes with Chelating Phosphinoalkylstannyl Ligands by Oxidative Addition of Sn-C Bonds

Mueller, Christine,Schubert, Ulrich

, p. 2181 - 2184 (2007/10/02)

Reaction of (Ph3P)4Pd with two equivalents of Ph2PCH2CH2-SnR3 (R = Ph, Me) gives the Pd(II) stannyl complexes trans-Pd(PPh2CH2CH2SnR2)2 (2) by oxidative addition of two Sn-R groups and elimination of R-R.Products corresponding to earlier steps of the reaction are obtained by the reaction of (Ph3P)2Pt(C2H4) with Ph2P(CH2)nSnR3 (n = 2, 3).The phenyl derivatives Ph2PnSnPh3 afford the Pt(II) complexes (Ph3P)(Ph)PtPPh2nSnPh2 (3), in which the two phosphorus atoms are cis-configurated, while Ph2PCH2CH2SnMe3 gives the Pt(IV) complex cis,cis,cis-(Me)2Pt(PPh2CH2CH2SnMe2)2 (3) as stable product.Key Words: Stannyl Complexes / Oxidative addition of Sn-C bonds / Phosphinoalkylstannanes

Post a RFQ

Enter 15 to 2000 letters.Word count: 0 letters

Attach files(File Format: Jpeg, Jpg, Gif, Png, PDF, PPT, Zip, Rar,Word or Excel Maximum File Size: 3MB)

1 Customer Service

What can I do for you?
Get Best Price

Get Best Price for 134110-44-4