134551-69-2 Usage
Explanation
The molecular formula represents the number of atoms of each element present in a molecule. In this case, the compound has 8 carbon atoms, 4 hydrogen atoms, 2 chlorine atoms, 2 nitrogen atoms, 1 oxygen atom, and 1 sulfur atom.
Explanation
A heterocyclic compound is a cyclic compound containing atoms of at least two different elements. In this case, the compound contains carbon, hydrogen, chlorine, nitrogen, oxygen, and sulfur atoms.
Explanation
The thiadiazole ring is a five-membered ring containing two nitrogen atoms and one sulfur atom. It is a part of the molecular structure of 1,2,5-Thiadiazol-3(2H)-one, 4-(2,4-dichlorophenyl)-.
Explanation
A phenyl group is a six-membered aromatic ring containing six carbon atoms and six hydrogen atoms. In 1,2,5-Thiadiazol-3(2H)-one, 4-(2,4-dichlorophenyl)-, the phenyl group is substituted with two chlorine atoms at the 2nd and 4th positions.
Explanation
The compound is used as a starting material or intermediate in the synthesis of various drugs and bioactive molecules due to its unique structure and diverse pharmacological properties.
Explanation
Studies have shown that 1,2,5-Thiadiazol-3(2H)-one, 4-(2,4-dichlorophenyl)has potential activities against fungi, bacteria, and tumors, as well as potential use as a herbicide and insecticide.
Explanation
The compound's unique structure and diverse pharmacological properties make it an important molecule for the development of new drugs and for use in agriculture, particularly in the development of new pesticides and herbicides.
Heterocyclic compound
Yes
Thiadiazole ring
Present
Phenyl group
Present
Pharmaceutical industry use
Building block for drug synthesis
Potential applications
Antifungal, antibacterial, antitumor, herbicide, and insecticide
Importance
Drug discovery and agricultural applications
Check Digit Verification of cas no
The CAS Registry Mumber 134551-69-2 includes 9 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 6 digits, 1,3,4,5,5 and 1 respectively; the second part has 2 digits, 6 and 9 respectively.
Calculate Digit Verification of CAS Registry Number 134551-69:
(8*1)+(7*3)+(6*4)+(5*5)+(4*5)+(3*1)+(2*6)+(1*9)=122
122 % 10 = 2
So 134551-69-2 is a valid CAS Registry Number.