13973-15-4 Usage
Uses
Used in Pharmaceutical Research and Development:
2-AMINO-5-FLUORO-5-(TRIFLUOROMETHYL)-4,5-DIHYDRO-1,3-THIAZOL-4-ONE is used as a key intermediate in the synthesis of potential drugs for various therapeutic purposes. Its unique structure and properties contribute to the development of new pharmaceutical compounds with improved efficacy and selectivity.
Used in Medicinal Chemistry:
In the field of medicinal chemistry, 2-AMINO-5-FLUORO-5-(TRIFLUOROMETHYL)-4,5-DIHYDRO-1,3-THIAZOL-4-ONE serves as a versatile building block for the design and synthesis of novel drug candidates. Its presence in the molecular structure can modulate the pharmacokinetic and pharmacodynamic properties of the resulting compounds, enhancing their therapeutic potential.
Used in Drug Discovery:
2-AMINO-5-FLUORO-5-(TRIFLUOROMETHYL)-4,5-DIHYDRO-1,3-THIAZOL-4-ONE is utilized in drug discovery processes to identify and optimize lead compounds with promising biological activities. Its unique structural features can be exploited to improve the potency, selectivity, and safety profiles of drug candidates, accelerating the development of innovative therapeutic agents.
Used in Chemical Synthesis:
Beyond its applications in pharmaceuticals, 2-AMINO-5-FLUORO-5-(TRIFLUOROMETHYL)-4,5-DIHYDRO-1,3-THIAZOL-4-ONE also finds use in various chemical synthesis processes. Its reactivity and functional groups make it a valuable component in the preparation of a wide range of organic and inorganic compounds, expanding its utility beyond the realm of drug development.
Check Digit Verification of cas no
The CAS Registry Mumber 13973-15-4 includes 8 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 5 digits, 1,3,9,7 and 3 respectively; the second part has 2 digits, 1 and 5 respectively.
Calculate Digit Verification of CAS Registry Number 13973-15:
(7*1)+(6*3)+(5*9)+(4*7)+(3*3)+(2*1)+(1*5)=114
114 % 10 = 4
So 13973-15-4 is a valid CAS Registry Number.
InChI:InChI=1/C4H2F4N2OS/c5-3(4(6,7)8)1(11)10-2(9)12-3/h(H2,9,10,11)