149695-99-8Relevant articles and documents
Tetraaza-λ3-diphospha-stanna-bicycloheptanes: Reactive Precursors of New Heterobicycles
Linti, Gerhard,Noeth, Heinrich,Schneider, Ellen,Storch, Wolfgang
, p. 619 - 630 (2007/10/02)
2,4,6,7-Tetraaza-1λ3,5λ3-diphospha-3-stannabicycloheptane (4) is obtained by stannazane cleavage of the diazadistannetidine (Me2SnNtBu)2 (2) with the diazadiphosphetidine (ClPNtBu)2 (1).A chloro derivative of 4, compound 8, is formed by substitution of one methyl group attached to the tin atom in 4 against chlorine in a 1:1 reaction with PhBCl2, while additional PhBCl2 leads to an exchange of the MeClSn against the PhB group to give 9.Oxidation of both phosphorus atoms of compound 4 with sulfur leads to 7.An unexpected introduction of a diphenyldiphosphane unit with formation of 11 proceeds by stannazane cleavage of 4 with PhPCl2.The structures of the bicyclic products 4, 7, 8, and 11 are ascertained by detailed NMR studies, particularly by means of 15N-NMR spectra, and by X-ray structure determinations.All heterobicycles contain a planar diazadiphosphetidine unit.The ring system 8 features an additional Sn-N bond due to transannular interaction of the tin atom with one of the nitrogen atoms of the four-membered P2N2 ring fragment.The PP bond distance in 11 with 2.175 Angstroem is one of the shortest found in heterocycles containing P2 units. Key Words: Tetraaza-diphospha-stanna-bicycloheptanes/ Tetraaza-tetraphospha-bicyclooctanes/1,3,2,4-Diazadiphosphetidines/1,3,2,4-Diazadistannetidines/SnN bond cleavage