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Ethoxy, 2,2,2-trifluoro-1-oxo- is a chemical with a specific purpose. Lookchem provides you with multiple data and supplier information of this chemical.

16040-26-9

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16040-26-9 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 16040-26-9 includes 8 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 5 digits, 1,6,0,4 and 0 respectively; the second part has 2 digits, 2 and 6 respectively.
Calculate Digit Verification of CAS Registry Number 16040-26:
(7*1)+(6*6)+(5*0)+(4*4)+(3*0)+(2*2)+(1*6)=69
69 % 10 = 9
So 16040-26-9 is a valid CAS Registry Number.

16040-26-9SDS

SAFETY DATA SHEETS

According to Globally Harmonized System of Classification and Labelling of Chemicals (GHS) - Sixth revised edition

Version: 1.0

Creation Date: Aug 17, 2017

Revision Date: Aug 17, 2017

1.Identification

1.1 GHS Product identifier

Product name trifluoro-acetyloxyl

1.2 Other means of identification

Product number -
Other names -

1.3 Recommended use of the chemical and restrictions on use

Identified uses For industry use only.
Uses advised against no data available

1.4 Supplier's details

1.5 Emergency phone number

Emergency phone number -
Service hours Monday to Friday, 9am-5pm (Standard time zone: UTC/GMT +8 hours).

More Details:16040-26-9 SDS

16040-26-9Downstream Products

16040-26-9Relevant academic research and scientific papers

Reactions of Trifluoromethyl Radicals. VI. Hydrogen Abstraction from Trifluoroacetic Acid and Trifluoroacetic (2H1)Acid

Arthur, Neville L.,David, Lennie F.

, p. 1535 - 1538 (2007/10/02)

The hydrogen abstraction reactions of CF3 radicals with CF3COOH and CF3COOD; CF3 + CF3COOH -> CF3H + CF3COO (1), CF3 + CF2COOD -> CF3D + CF3COO (2) have been studied in the temperature ranges 102-225 deg C and 153-275 deg C respectively.The rate constants, based on the value of 1013.36 cm3mol-1s-1 for the recombination of CF3 radicals, are given by (k in cm3 mol-1 s-1 and E in J mol-1): logk1 = (10.17 +/- 0.12) - (33140 +/- 970)/19.145T, logk2 = (9.51 +/- 0.11) - (46090 +/- 1010)/19.145T.

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