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(1,2-bis(di-p-tolylphosphino)ethane)Pt(CO3) is a chemical with a specific purpose. Lookchem provides you with multiple data and supplier information of this chemical.

181354-64-3

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181354-64-3 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 181354-64-3 includes 9 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 6 digits, 1,8,1,3,5 and 4 respectively; the second part has 2 digits, 6 and 4 respectively.
Calculate Digit Verification of CAS Registry Number 181354-64:
(8*1)+(7*8)+(6*1)+(5*3)+(4*5)+(3*4)+(2*6)+(1*4)=133
133 % 10 = 3
So 181354-64-3 is a valid CAS Registry Number.

181354-64-3Downstream Products

181354-64-3Relevant academic research and scientific papers

Syntheses, Spectra, and Structures of (Diphosphine)platinum(II) Carbonate Complexes

Andrews, Mark A.,Gould, George L.,Klooster, Wim T.,Koenig, Kristina S.,Voss, Eric J.

, p. 5478 - 5483 (1996)

A variety of (diphosphine)platinum(II) carbonate complexes, (LL)Pt(CO3), are readily prepared from the corresponding (diphosphine)platinum dichlorides by treatment with silver carbonate in dichoromethane solution provided that water is present. This reaction also permits facile preparation of analogous 13C-labeled complexes. The carbonate ligands in these complexes have been characterized by IR and 13C NMR spectroscopy. Alternative preparative routes involve conversion of the precursor dichlorides to the corresponding dialkoxides or diphenoxides, followed by treatment with water and carbon dioxide. Various reaction intermediates have been spectroscopically observed in the latter syntheses. Two crystalline modifications of (Ph2PCH2CH2CH2PPh 2)Pt(CO3), one with and one without a dichloromethane of solvation, have been studied by single-crystal X-ray diffraction. Crystal data for PtP2O3C28H26: P21/c, Z = 4, T = 200 K, a = 10.362(8) ?, b = 14.743(6) ?, c = 19.183(10) ?, β = 122.69(6)°. Crystal data for PtP2O3C28H26·CH 2Cl2: P21/c, Z = 4, T ≈ 298 K, a = 11.744(2) ?, b = 15.526(3) ?, c = 15.866(3) ?, β = 101.58(1)°.

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