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Pt(C3H4CH3)(P(C6H5)3)2(1+)*Cl(1-)=[Pt(C3H4CH3)(P(C6H5)3)2]Cl is a chemical with a specific purpose. Lookchem provides you with multiple data and supplier information of this chemical.

215435-76-0

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215435-76-0 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 215435-76-0 includes 9 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 6 digits, 2,1,5,4,3 and 5 respectively; the second part has 2 digits, 7 and 6 respectively.
Calculate Digit Verification of CAS Registry Number 215435-76:
(8*2)+(7*1)+(6*5)+(5*4)+(4*3)+(3*5)+(2*7)+(1*6)=120
120 % 10 = 0
So 215435-76-0 is a valid CAS Registry Number.

215435-76-0Upstream product

215435-76-0Relevant academic research and scientific papers

LIGAND-SUBSTITUTION REACTIONS OF NEUTRAL AND CATIONIC ALLYL(CYCLO-OCTA-3,5-DIENE)PLATINUM COMPLEXES

Boag, Neil M.,Green, Michael,Spencer, John L.,Stone, F. Gordon A.

, p. 1208 - 1219 (2007/10/02)

Treatment of the compound (X=Cl or Br; cod=cyclo-octa-1,5-diene) with pyridine (py) affords 3-C3H5)(py)>.In solution these complexes dimerise to form allyl-bridged binuclear species.Reaction of the complex > with allyl halides, or reaction of (X=Cl, allyl=C3H5 or C3H4Ph-3; X=Br, allyl=C3H5 or C3H4Me-3) with 1 mol of P(C6H11)3 affords the compounds 3-allyl).Addition of 2 mol of PPh3 or P(C6H11)3, or 1 equivalent of Ph2PCH2CH2PPh2 (dppe), affords complexes of the type .Treatment of the salts 3-allyl)(cod)> (allyl=C3H5 or C3H4Me-3) with py, PPh3, or dppe gives 3-allyl)(L2)BF4> (L2=2py, 2PPh3, or dppe).In contrast, 1 mol of PPh3 followed by 1 equivalent of CO, ButNC, or py yields the complexes 3-C3H5)(PPh3)L> (L = CO, CNBut, or py) possibly via the intermediacy of 3-C3H5)(PPh3)>.Excess of ButNC or py affords the ?-allylic species .In a similar manner, the tris(trimethyl phosphite) complexes 3> (allyl=C3H5, C3H4Me-3, or C3H4Ph-3) have been synthesized.Detailed n.m.r. studies (1H, 13C, 31P, variable-temperature) of these complexes has led to an understanding of their behaviour in solution.

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