6-methyl-4,5,6,7-tetrahydro-1(2)H-indazole-3-carboxylic acid ethyl ester is a complex organic compound with the molecular formula C12H17N2O2. It is a derivative of indazole, a bicyclic aromatic compound, with a methyl group at the 6th position and a carboxylic acid group at the 3rd position. The carboxylic acid is esterified with an ethyl group, making it an ethyl ester. 6-methyl-4,5,6,7-tetrahydro-1(2)H-indazole-3-carboxylic acid ethyl ester is characterized by its tetrahydro structure, which means that four hydrogen atoms have been added across the molecule's double bonds, leading to a fully saturated ring system. It is likely to be found in pharmaceutical or chemical research settings, potentially as an intermediate in the synthesis of various drugs or other organic compounds.
The CAS Registry Mumber 4492-03-9 includes 7 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 4 digits, 4,4,9 and 2 respectively; the second part has 2 digits, 0 and 3 respectively. Calculate Digit Verification of CAS Registry Number 4492-03: (6*4)+(5*4)+(4*9)+(3*2)+(2*0)+(1*3)=89 89 % 10 = 9 So 4492-03-9 is a valid CAS Registry Number.