Cas 455884-01-2,[C5H5RuBr(As(C6H5)3)CH2CHCH2](1+)*PF6(1-)=[C5H5RuBr(As(C6H5)3)CH2CHCH2]PF6

455884-01-2

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Basic information

Product Name: [C₅H₅RuBr(As(C₆H₅)3)CH₂CHCH₂]⁽¹⁺⁾*PF₆^(1-)=[C₅H₅RuBr(As(C₆H₅)3)CH₂CHCH₂]PF₆
Synonyms:
CAS NO:455884-01-2
Molecular Formula:
Molecular Weight: 738.344
EINECS: N/A
Product Categories: N/A

Chemical Properties

Melting Point: N/A
Boiling Point: N/A
Flash Point: N/A
Appearance: N/A
Density: N/A
Refractive Index: N/A
Storage Temp.: N/A
Solubility: N/A
CAS DataBase Reference: [C₅H₅RuBr(As(C₆H₅)3)CH₂CHCH₂]⁽¹⁺⁾*PF₆^(1-)=[C₅H₅RuBr(As(C₆H₅)3)CH₂CHCH₂]PF₆(CAS DataBase Reference)
NIST Chemistry Reference: [C₅H₅RuBr(As(C₆H₅)3)CH₂CHCH₂]⁽¹⁺⁾*PF₆^(1-)=[C₅H₅RuBr(As(C₆H₅)3)CH₂CHCH₂]PF₆(455884-01-2)
EPA Substance Registry System: [C₅H₅RuBr(As(C₆H₅)3)CH₂CHCH₂]⁽¹⁺⁾*PF₆^(1-)=[C₅H₅RuBr(As(C₆H₅)3)CH₂CHCH₂]PF₆(455884-01-2)

Safety Data

Hazard Codes: N/A
Statements: N/A
Safety Statements: N/A
WGK Germany:
RTECS:
HazardClass: N/A
PackingGroup: N/A
Hazardous Substances Data: 455884-01-2(Hazardous Substances Data)

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Check Digit Verification of cas no

The CAS Registry Mumber 455884-01-2 includes 9 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 6 digits, 4,5,5,8,8 and 4 respectively; the second part has 2 digits, 0 and 1 respectively.
Calculate Digit Verification of CAS Registry Number 455884-01:
(8*4)+(7*5)+(6*5)+(5*8)+(4*8)+(3*4)+(2*0)+(1*1)=182
182 % 10 = 2
So 455884-01-2 is a valid CAS Registry Number.

455884-01-2Upstream product

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455884-01-2Relevant academic research and scientific papers

Synthesis, characterization, and reactivity of half-sandwich Ru(II) complexes containing phosphine, arsine, stibine, and bismutine ligands

Becker, Eva,Slugovc, Christian,Rüba, Eva,Standfest-Hauser, Christina,Mereiter, Kurt,Schmid, Roland,Kirchner, Karl

, p. 55 - 63 (2007/10/03)

The synthesis and some reactions of the Ru(II) and Ru(IV) half-sandwich complexes [RuCp(EPh3)(CH3CN)2]+ (E = P, As, Sb Bi) and when the former is weaker, that is in going down the series. Thus in the case of Bi,

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