Cas 479622-10-1,(CH3)3CCH2C2(CH3)2N2(C6H3(CH(CH3)2)2)2MnCH2C(CH3)3

479622-10-1

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Basic information

Product Name: (CH₃)3CCH₂C₂(CH₃)2N₂(C₆H₃(CH(CH₃)2)2)2MnCH₂C(CH₃)3
Synonyms: (CH₃)3CCH₂C₂(CH₃)2N₂(C₆H₃(CH(CH₃)2)2)2MnCH₂C(CH₃)3
CAS NO:479622-10-1
Molecular Formula:
Molecular Weight: 601.862
EINECS: N/A
Product Categories: N/A

Chemical Properties

Melting Point: N/A
Boiling Point: N/A
Flash Point: N/A
Appearance: N/A
Density: N/A
Refractive Index: N/A
Storage Temp.: N/A
Solubility: N/A
CAS DataBase Reference: (CH₃)3CCH₂C₂(CH₃)2N₂(C₆H₃(CH(CH₃)2)2)2MnCH₂C(CH₃)3(CAS DataBase Reference)
NIST Chemistry Reference: (CH₃)3CCH₂C₂(CH₃)2N₂(C₆H₃(CH(CH₃)2)2)2MnCH₂C(CH₃)3(479622-10-1)
EPA Substance Registry System: (CH₃)3CCH₂C₂(CH₃)2N₂(C₆H₃(CH(CH₃)2)2)2MnCH₂C(CH₃)3(479622-10-1)

Safety Data

Hazard Codes: N/A
Statements: N/A
Safety Statements: N/A
WGK Germany:
RTECS:
HazardClass: N/A
PackingGroup: N/A
Hazardous Substances Data: 479622-10-1(Hazardous Substances Data)

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Check Digit Verification of cas no

The CAS Registry Mumber 479622-10-1 includes 9 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 6 digits, 4,7,9,6,2 and 2 respectively; the second part has 2 digits, 1 and 0 respectively.
Calculate Digit Verification of CAS Registry Number 479622-10:
(8*4)+(7*7)+(6*9)+(5*6)+(4*2)+(3*2)+(2*1)+(1*0)=181
181 % 10 = 1
So 479622-10-1 is a valid CAS Registry Number.

479622-10-1Upstream product

479622-10-1Downstream Products

479622-10-1Relevant academic research and scientific papers

Reaction of [MnII(CH2tBu)2] with bidentate diimine ligands: From simple base adducts to C-C activation of the ligand

Riollet, Virginie,Coperet, Christophe,Basset, Jean-Marie,Rousset, Laurence,Bouchu, Denis,Grosvalet, Laurent,Perrin, Monique

, p. 3025 - 3027 (2002)

Ligand transformations that depend on the substitution patterns of the diimine ligands occur upon their complexation with Mn11 dialkyl complexes. For example the 1,3-migration of the neopentyl unit from Mn to a carbon atom and the 1,2-migration of the methyl in the putative intermediate 1 give the product 2.

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