51093-54-0 Usage
Explanation
The molecular formula represents the number of atoms of each element present in a molecule. In this case, the compound has 6 carbon atoms, 7 hydrogen atoms, 1 fluorine atom, 2 nitrogen atoms, 1 oxygen atom, and 1 sulfur atom.
Explanation
The IUPAC name is a systematic method of naming chemical compounds, ensuring that each compound has a unique and unambiguous name.
Explanation
The compound contains a heterocyclic ring, which is a ring of atoms with at least one atom being different from carbon, in this case, a thiadiazole ring.
Explanation
The thiadiazole ring is a five-membered ring with two nitrogen atoms and one sulfur atom, contributing to the compound's unique properties.
Explanation
The presence of a fluorine atom in the molecule can significantly affect its reactivity, stability, and potential applications.
Explanation
Due to its unique chemical structure, 1,2,4-Thiadiazol-5(2H)-one,3-fluoro-2-(1-methylethyl)-(9CI) may have potential applications in the development of new drugs, although further research is needed to determine its specific properties and uses.
Explanation
The compound's chemical structure and properties make it a subject of interest in various scientific fields, including organic chemistry, materials science, and pharmaceutical chemistry.
Explanation
As with any new chemical compound, further research is necessary to fully understand its properties, potential applications, and any possible side effects before it can be used in practical applications.
Chemical Structure
Heterocyclic organic compound
Thiadiazole Ring
Contains sulfur and nitrogen atoms
Fluorine Atom
Present in the molecule
Potential Applications
Pharmaceutical industry, drug development
Field of Interest
Organic chemistry, materials science, pharmaceutical chemistry
Further Research
Required to determine specific properties, uses, and potential side effects
Check Digit Verification of cas no
The CAS Registry Mumber 51093-54-0 includes 8 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 5 digits, 5,1,0,9 and 3 respectively; the second part has 2 digits, 5 and 4 respectively.
Calculate Digit Verification of CAS Registry Number 51093-54:
(7*5)+(6*1)+(5*0)+(4*9)+(3*3)+(2*5)+(1*4)=100
100 % 10 = 0
So 51093-54-0 is a valid CAS Registry Number.
