54766-31-3

Upstream product

• 12080-32-9 dichloro(1,5-cyclooctadiene)platinum(ll) 
• 63911-00-2 {PtH2(μ-H)(μ-dppm)2}PF6 
• 2071-20-7 bis-diphenylphosphinomethane 
• 106373-22-2 bis-μ-bis(diphenylphosphino)methane-μ-hydrido-bis-[chloroplatinum(II)] chloride 
• 63910-98-5 bis-μ-bis(diphenylphosphino)methane-μ-hydrido-bis-[hydridoplatinum(II)] chloride 

Downstream Products

• 64387-52-6 {Pt2(CO)Cl(μ-1,2-bis(diphenylphosphino)methane)2}Cl 
• 146814-27-9 {Pt₂((C₆H₅)2PCH₂P(C₆H₅)2)2(NC₅H₂(CH₃)3)Cl}⁽¹⁺⁾*{PF₆}^(1-)*C₃H₆O={Pt₂((C₆H₅)2PCH₂P(C₆H₅)2)2(NC₅H₂(CH₃)3)Cl}{PF₆}*C₃H₆O 
• 106373-22-2 [Pt₂Cl₂(H)(((C₆H₅)2P)2CH₂)2]⁽¹⁺⁾*Cl^(1-)=[Pt₂Cl₂(H)(((C₆H₅)2P)2CH₂)2]Cl 
• 82620-40-4 bis-μ-[bis(diphenylphosphino)methane]chloro(trichlorostannio)diplatinum(Pt-Pt) 
• 106373-22-2 bis-μ-bis(diphenylphosphino)methane-μ-hydrido-bis-[chloroplatinum(II)] chloride 
• 82620-41-5 Pt₂((C₆H₅)2PCH₂P(C₆H₅)2)2(SnCl₃)2 

Relevant academic research and scientific papers

Binuclear reductive elimination reactions in diplatinum complexes: Synthesis of hydridoplatinum(I) complexes

The complex [Pt2H2(μ-H)(μ-dppm)2][PF6] (1) (dppm = Ph2PCH2PPh2) reacts with tertiary phosphine ligands to give H2 and the hydridoplatinum(I) complexes [Pt2HL(μ-dppm)2][PF6] (4, L = η1-dppm; 5, L = PMe2Ph; 6, L = PMePh2; 7, L = PPh3). Complex 4 is also obtained by the reduction of [Pt(dppm)2][PF6]2 with sodium borohydride. Study of the 1H and 31P NMR spectra of 4-7 is in accord with the presence of Pt-Pt bonds and, in the case of 4, shows that its structure in solution is similar to that previously determined in the solid state by an X-ray investigation. Methanethiol reacts reversibly with 4 to give [Pt2H2(μ-SMe)(μ-dppm)2][PF6]. Attempts to prepare diplatinum(0) complexes by deprotonation of 4 or 7 were unsuccessful.