594840-57-0 Usage
Molecular structure
1-Pyrrolidinecarboxylic acid, 2-[(1S)-4-ethoxy-1-hydroxy-4-oxo-2-butynyl]-, 1,1-dimethylethyl ester, (2S)is an ester derivative of 1-Pyrrolidinecarboxylic acid with an ethoxy group, a hydroxy group, and a butynyl group attached to it.
Stereochemistry
The presence of (1S) and (2S) configurations in the chemical name indicates the stereochemistry of the molecule, which is the three-dimensional arrangement of atoms in space.
Ester group
The ester group (-COO-) is formed by the combination of a carboxylic acid and an alcohol, which is present in 1-Pyrrolidinecarboxylic acid,
2-[(1S)-4-ethoxy-1-hydroxy-4-oxo-2-butynyl]-, 1,1-dimethylethyl ester,
(2S)- as the 1-Pyrrolidinecarboxylic acid is esterified with the butynyl group.
Ethoxy group
The ethoxy group (-OCH2CH3) is an ether functional group derived from ethanol, which is attached to the 4-position of the butynyl group.
Hydroxy group
The hydroxy group (-OH) is present at the 1-position of the butynyl group, indicating the presence of an alcohol functional group.
Butynyl group
The butynyl group (-C≡CCH2CH3) is a four-carbon alkyne chain with one triple bond and one single bond, which is attached to the 2-position of the ester.
Dimethylethyl ester
The 1,1-dimethylethyl ester indicates that the ester is formed by the reaction of 1-Pyrrolidinecarboxylic acid with a molecule of 1,1-dimethylethyl alcohol, resulting in a quaternary carbon atom.
Potential applications
This chemical compound may have potential pharmaceutical or biological applications due to its unique structure and functional groups, but further research is needed to fully understand its properties and potential uses.
Check Digit Verification of cas no
The CAS Registry Mumber 594840-57-0 includes 9 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 6 digits, 5,9,4,8,4 and 0 respectively; the second part has 2 digits, 5 and 7 respectively.
Calculate Digit Verification of CAS Registry Number 594840-57:
(8*5)+(7*9)+(6*4)+(5*8)+(4*4)+(3*0)+(2*5)+(1*7)=200
200 % 10 = 0
So 594840-57-0 is a valid CAS Registry Number.