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6181-00-6

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6181-00-6 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 6181-00-6 includes 7 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 4 digits, 6,1,8 and 1 respectively; the second part has 2 digits, 0 and 0 respectively.
Calculate Digit Verification of CAS Registry Number 6181-00:
(6*6)+(5*1)+(4*8)+(3*1)+(2*0)+(1*0)=76
76 % 10 = 6
So 6181-00-6 is a valid CAS Registry Number.

6181-00-6Relevant articles and documents

INTERET DE LA DEUTERIATION DES MOLECULES ORGANOSTANNIQUES EN RMN DE 119Sn. II. RELATION DE TYPE KARPLUS POUR 3J(SnD) ET STEREOCHIMIE DE DEUTERIOSTANNATION DE QUELQUES HYDROCARBURES ETHYLENIQUES

Quintard, Jean-Paul,Degueil-Castaing, Marie,Barbe, Bernard,Petraud, Michel

, p. 41 - 62 (1982)

Whenever selective deuterium labelling is easily performed a new proficiency is given to FT 119Sn NMR by the determination of the angular dependence of 3J(SnD).Using model molecules with structures being checked by other methods, the angular dependence of 3J(SnD) has been shown to follow a Karplus-like relationship.Illustrative examples for the qualitative and quantitative analysis of diastereoisomeric organotin compounds are described.This method allows for instance, a fast and convenient determination of the stereochemistry of alkene deutero- and hydro-stannations.

The reactions of Ir(CO)Cl(PPh3)2 with HSnPh 3

Adams, Richard D.,Fang, Fang,Smith, Mark D.,Zhang, Qiang

, p. 2904 - 2909 (2011/08/09)

A reinvestigation of the reaction of Ir(CO)Cl(PPh3)2, 1 with HSnPh3 has revealed that the oxidative-addition product Ir(CO)Cl(PPh3)2(H)(SnPh3), 2 has the H and SnPh3 ligands in cis-related coordination sites. Compound 2 reacts with a second equivalent of HSnPh3 by a Cl for H ligand exchange to yield the new compound H2Ir(CO)(SnPh3)(PPh 3)2, 3. Compound 3 contains two cis- related hydride ligands. Under an atmosphere of CO, 1 reacts with HSnPh3 to replace the Cl ligand with SnPh3 and one of the PPh3 ligands with a CO ligand and also adds a second equivalent of CO to yield the 5-coordinate complex Ir(CO)3(SnPh3)(PPh3), 4. Compound 4 reacts with HSnPh3 by loss of CO and oxidative addition of the Sn-H bond to yield the 6-coordinate complex HIr(CO)2(SnPh 3)2(PPh3), 5 that contains two trans-positioned SnPh3 ligands.

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