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[Ti(OC(C6H5)2CH(C6H5)CHCHN(C6H3(CH(CH3)2)2))2] is a chemical with a specific purpose. Lookchem provides you with multiple data and supplier information of this chemical.

681210-90-2

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681210-90-2 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 681210-90-2 includes 9 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 6 digits, 6,8,1,2,1 and 0 respectively; the second part has 2 digits, 9 and 0 respectively.
Calculate Digit Verification of CAS Registry Number 681210-90:
(8*6)+(7*8)+(6*1)+(5*2)+(4*1)+(3*0)+(2*9)+(1*0)=142
142 % 10 = 2
So 681210-90-2 is a valid CAS Registry Number.

681210-90-2Upstream product

681210-90-2Downstream Products

681210-90-2Relevant academic research and scientific papers

Synthesis and structure of the first homoleptic 1-Aza-1,3-diene titanium complex: A tightrope walk between ligand coordination and ligand coupling

Scholz, Joachim,Kahlert, Steffen,G?rls, Helmar

, p. 1594 - 1603 (2004)

The reaction of TiCl4(THF)2 or ZrCl4(THF)2 with Mg in the presence of 1-aza-1,3-dienes (1) has been investigated. Reduction of TiCl4(THF)2 with 2 equiv of Mg in the presence of 2 equiv of (R1)N=CHC(R2)=CH(Ph) yields the first homoleptic 1-aza-1,3-diene complex, [Ti-{N(R1)CH=C(R2)CH(Ph)}2] (7), but only if the 1-aza-1,3-diene is substituted by a sterically demanding group at the nitrogen atom (1b: R1 = C6H3-2,6-iPr2, R2 = H). X-ray crystallography indicates a σ2,π coordination of the heterodienes, which are reduced to 1-azabut-2-ene-1,4-diyl dianions to form folded 1-aza-2-titanacyclopent-4-ene rings. As a byproduct, the bicyclic complex [{N(R1)CH=C(R2)CH(Ph)}Ti{N(R1) CH=C(R2)CH(Ph)CH{C(R2)=CH- (Ph)}N(R1)] (8) was isolated, which is believed to arise from C=N insertion of 1b into the Ti-C bond of the intermediate [{N(R1)CH=C(R2)CH(Ph)} TiCl2], followed by the coordination of a further 1-aza-1,3-diene ligand. The analogous bicyclic zirconium complex [{N(R1)CH= C(R2)CH(Ph)}ZrN{(R1)CH=C(R2)CH(Ph) CH{C(R2)=CH(Ph)N(R1)] (6: R1 = cyclo-C6H11, R2 = Me) is the only available product when the reduction of ZrCl4(THF)2 is performed in the presence of the 1-aza-1,3-diene (cyclo-C6H11)N=CHC(Me)=CHPh (1a), which is substituted by a sterically less demanding group at the terminal nitrogen atom. Addition of 2 equiv of benzophenone to 7 affords the titanium complex [Ti{OCPh2CH(Ph)C(R2)=CHN(R1)}2] (9). The solid-state structure of 9 shows the titanium in a distorted-tetrahedral environment, being the center of two folded oxazatitanacycloheptene rings.

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