70415-58-6 Usage
General Description
(Z)-1,3-Butadien-1-ol, also known as isoprene alcohol, is a chemical compound with the molecular formula C4H6O. It is a colorless liquid with a slightly sweet odor. (Z)-1,3-Butadien-1-ol is primarily used in the synthesis of various polymers, including synthetic rubbers and plastics. Isoprene alcohol is also used in the production of fragrances and as a chemical intermediate in the synthesis of other organic compounds. It is a highly flammable and reactive compound and should be handled with care. Additionally, it is important to note that (Z)-1,3-Butadien-1-ol is a potential irritant to the skin, eyes, and respiratory system, and exposure to high concentrations should be avoided.
Check Digit Verification of cas no
The CAS Registry Mumber 70415-58-6 includes 8 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 5 digits, 7,0,4,1 and 5 respectively; the second part has 2 digits, 5 and 8 respectively.
Calculate Digit Verification of CAS Registry Number 70415-58:
(7*7)+(6*0)+(5*4)+(4*1)+(3*5)+(2*5)+(1*8)=106
106 % 10 = 6
So 70415-58-6 is a valid CAS Registry Number.
InChI:InChI=1/C4H6O/c1-2-3-4-5/h2-5H,1H2/b4-3-
70415-58-6Relevant articles and documents
Simple Enols. 5. (Z)- and (E)-1-Hydroxy-1,3-butadiene
Capon, Brian,Guo, Bozhang
, p. 5144 - 5147 (1988)
(Z)- and (E)-1-hydroxybutadiene have been generated from their trimethylsilyl derivatives in slightly acidic aqueous acetonitrile and CH3OH-DMSO mixtures and characterized by NMR spectroscopy.The kinetics and products of ketonization of both dienols have been investigated.In aqueous solution they yield mixtures of (E)-2-butenal and 3-butenal whose proportions depend on pH.Analysis of the variation of product composition with pH indicates that (E)-1-hydroxybutadiene yields 90.1, 28.0, and 44.7percent of (E)-2-butenal in the H3O+, H2O, and HO--catalyzed reactions, whereas (Z)-1-hydroxybutadiene yields 69.8, 17.2, and 19.6percent.It is suggested that transmission of positive charge to the oxygen in the transition state for protonation at the 4-position is more efficient with the E than with the Z isomer, possibly because it is easier for the former to attain a planar conformation.No evidence was found for a mechanism that involves a cyclic transition state for the spontaneous ketonization of (Z)-butadienol.