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Tripropan-2-ylstibane is a chemical compound with the molecular formula C9H22Sb. It is an organoantimony compound, which means it contains carbon, hydrogen, and antimony atoms. tripropan-2-ylstibane is characterized by a central antimony atom bonded to three propyl groups (each consisting of three carbon atoms) and a single hydrogen atom. Tripropan-2-ylstibane is a colorless liquid at room temperature and is relatively stable, although it can decompose upon exposure to heat or light. It is not commonly found in nature and is typically synthesized in laboratories for research purposes, particularly in the field of organometallic chemistry. Due to its potential toxicity and the heavy metal content, it is important to handle tripropan-2-ylstibane with care and in accordance with proper safety protocols.

73300-45-5

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73300-45-5 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 73300-45-5 includes 8 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 5 digits, 7,3,3,0 and 0 respectively; the second part has 2 digits, 4 and 5 respectively.
Calculate Digit Verification of CAS Registry Number 73300-45:
(7*7)+(6*3)+(5*3)+(4*0)+(3*0)+(2*4)+(1*5)=95
95 % 10 = 5
So 73300-45-5 is a valid CAS Registry Number.

73300-45-5Relevant academic research and scientific papers

Novel triaikylstlbane iridium(I) and iridium(III) complexes including the X-ray crystal structure of five-coordinate [IrCl(C2H4)2(SbiPr3)2]

Werner, Helmut,Ortmann, Dagmara A.,Gevert, Olaf

, p. 411 - 417 (2007/10/03)

The reaction of [IrCl(C8H14)2]2 (2) with SbiPr3 in the presence of H2 yields the dihydridoiridium(III) complex cis,mer[IrH2Cl(SbiPr3)3] (3) which on treatment with CO and with HC≡CR (R = Ph, CO2Me) affords the octahedral derivatives [IrH2Cl(CO)(SbiPr3)2] (4) and [IrHCl(C=CR)(SbiPr3)3] (5, 6), respectively. The stibane ligand trans to hydride in 5 and 6 is rather labile and, therefore, 5 and 6 react with pyridine to give [IrHCl(C=CR)(py)(SbiPr3))2] (7, 8). Five-coordinate bis-(stibane)iridium(I) complexes [IrCl(C2H4)2(SbR3)2] (10-12) were prepared from [IrCl(C2H4)2]2 (9) and four equiv. of SbR3 (R = iPr, Me, Ph). The X-ray crystal structural analysis of 10 reveals a distorted trigonal-bipyramidal geometry around the metal center with one stibane ligand and the two olefinic ligands in the equatorial plane. Compound 10 reacts with NaC5H5 to yield [C5H5Ir(C2H4)(SbiPr3)] (13) and with different alkynes by partial or complete displacement of the ethene ligands to give trans-[IrCl(PhC≡CPh)(SbiPr3)2] (14), [IrHCl(C≡CTol)(C2H4)(SbiPr3)2] (15), and trans-[IrCl-{ = C = C(SiMe3)R}(SbiPr3)2] (16, 17), respectively. VCH Verlagsgescllschaft mbH 1996.

DARSTELLUNG UND SPECTROSKOPISCHE UNTERSUCHUNGEN VON METHYL- UND ISOPROPYLANTIMONHALOGENIDEN

Breunig, H. J.,Kanig, W.

, p. 149 - 160 (2007/10/02)

Halogenations of iPr3Sb yield the dihalides iPr3SbX2 X=Cl, Br, I.These compounds decompose thermally to iPrX and iPr2SbX.Halogenations of iPr2SbX produce unstable trihalides iPr2SbX3, which eliminate iPrX to give iPrSbX2.By this procedure only the bromides and iodides iPr2SbX and iPrSbX2 X=Br, I can be obtained in useful yields and purities.Pure iPrSbCl2 and iPr3Sb are products of exchange reaction of iPr2SbCl.The purity of the known methylcompounds Me2SbX X=Cl, Br, I obtained by decomposition of Me3SbX2 has been examined.MeSbI2 and Me3Sb are formed from Me2SbI.Previously unpublished ir-, 1H-nmr-, and ms-data of iPr3SbX2, R2SbX and RSbX2 R=Me, iPr, X=Cl, Br, I are discussed.

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