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N(CH3)4(1+)*Mn(CO)5(1-) = N(CH3)4Mn(CO)5 is a chemical with a specific purpose. Lookchem provides you with multiple data and supplier information of this chemical.

74343-84-3

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74343-84-3 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 74343-84-3 includes 8 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 5 digits, 7,4,3,4 and 3 respectively; the second part has 2 digits, 8 and 4 respectively.
Calculate Digit Verification of CAS Registry Number 74343-84:
(7*7)+(6*4)+(5*3)+(4*4)+(3*3)+(2*8)+(1*4)=133
133 % 10 = 3
So 74343-84-3 is a valid CAS Registry Number.

74343-84-3Upstream product

74343-84-3Relevant academic research and scientific papers

Mechanism of Reductive Elimination of Acetophenone from N(CH3)4+-

Casey, Charles P.,Scheck, Daniel M.

, p. 2728 - 2731 (1980)

Decomposition of N(CH3)4+- (1) in the presence og P(C6H5)3 gives N(CH3)4+Mn(CO)4- and provides evidence for a Mn(CO)4- intermediate.Decomposition of 90percent 13C-acetyl labeled N(CH3)4+- (1A) gave 42.7percent 13C-labeled acetophenone.Decomposition of 90percent 13C-benzoyl labeled N(CH3)4+- (1b) gave 6.0percent 13C-labeled acetophenone.These results are interpreted in terms of a mechanism involving loss of CO from 1 and formation of a five-coordinate intermediate Mn(CO)3(COCH3)(COC6H5)- (2), which is in rapid equilibrium with benzoylmethyl intermediate Mn(CO)4(CH3)(COC6H5)- (3).Conversion of 3 to the acetylphenyl intermediate Mn(CO)4(C6H5)(COCH3)- (4) is followed by reductive elimination to give acetophenone.

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