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[Rh(μ-pyrazolate)(1,5-cyclooctadiene)]2 is a rhodium-based coordination complex, consisting of two rhodium atoms bridged by a pyrazolate ligand. The 1,5-cyclooctadiene ligand is coordinated to each rhodium atom, forming a unique structure. [Rh(μ-pyrazolate)(1,5-cyclooctadiene)]2 is of interest in the field of organometallic chemistry and catalysis, as it exhibits unique electronic and geometric properties that can influence its reactivity and potential applications in various chemical transformations. The pyrazolate ligand plays a crucial role in stabilizing the complex and modulating its electronic properties, while the cyclooctadiene ligand provides a flexible, unsaturated environment that can participate in various chemical reactions. Overall, [Rh(μ-pyrazolate)(1,5-cyclooctadiene)]2 is a fascinating example of a rhodium complex with potential applications in catalysis and materials science.

77244-03-2

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77244-03-2 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 77244-03-2 includes 8 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 5 digits, 7,7,2,4 and 4 respectively; the second part has 2 digits, 0 and 3 respectively.
Calculate Digit Verification of CAS Registry Number 77244-03:
(7*7)+(6*7)+(5*2)+(4*4)+(3*4)+(2*0)+(1*3)=132
132 % 10 = 2
So 77244-03-2 is a valid CAS Registry Number.

77244-03-2Relevant academic research and scientific papers

Reactions of BF4 with alkynes: synthesis of new hydride-vinyl iridium(III) complexes

Esteruelas, Miguel A.,Garcia, Maria P.,Martin, Marta,Nuernberg, Oliver,Oro, Luis A.,Werner, Helmut

, p. 249 - 258 (2007/10/02)

One of the two acetone ligands in the complex BF4 (1) is displaced by pyrazole (Hpz) to give BF4 (2).Treatment of 2 with methyl propiolate and acetylenedicarboxylic dimethyl ester leads to the cationic complexes (3), (4) and (5).The molecular structure of 3 has been determined by X-ray analysis. 3 crystallizes with an acetone molecule in the lattice, in the space group P21/m with a=9.661(3) Angstroem, b=22.903(3) Angstroem, c=11.056(3) Angstroem and β=99.82(1)o.The coordination around the iridium atom is a distorted octahedron with the two phosphorus atoms of the triphenylphosphine ligands occupying trans positions.The equatorial plane is formed by the α-C atom, the oxygen atom of the carbonyl group of the ester, the hydride and a nitrogen atom of the pyrazole ligand. 3 reacts with 4-1,5-COD)>2> to give, via a redistribution reaction, (6) and 4-1,5-COD)>2>.The methanol molecule of 6 is displaced by P(OMe)3 and CO to yield (L=P(OMe)3 (7) or CO (8)).The vinyl complexes BF4 (9) and (10) were prepared by reaction of 3 with P(OMe)3 and Cl- respectively.Complex 10 reacts with 4-1,5-COD)>2> to afford the heterobimetallic compound 4-1,5-COD)> (11). Key words: Iridium; Hydride; Vinyl; Alkyne

GOLD(I) AND PLATINUM(II) AZOLATES AS LIGANDS IN CATIONIC RHODIUM(I) COMPLEXES

Uson, R.,Oro, L. A.,Ciriano, M. A.,Pinillos, M. T.,Cabeza, J. A.

, p. 249 - 256 (2007/10/02)

Several cationic heterometallic rhodium complexes have been obtained by using the complexes ImAuPPh3 or (az)2Pt(dpe) (az=imidazolate (Im) or pyrazolate (Pz) anions) as ligands.Attempts to prepare rhodium(I)-gold(I) derivatives containing pyrazolate-bridging ligands proved unsuccessful, rearrangements giving the complexes 2 and ClO4, ClO4 or AuClPPh3 as end-products.

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