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The chemical compound "Zr(CH2C6H5)2Cl2((CH3)2NCH2CH2N(CH3)2)" is a complex organometallic compound consisting of a zirconium (Zr) center. It features two phenyl groups (C6H5) bonded to the zirconium atom through methylene (CH2) bridges, and two chloride (Cl) ligands. Additionally, it has a bidentate ligand, bis((dimethylamino)methyl)amine, which chelates the zirconium center through its two nitrogen atoms. Zr(CH2C6H5)2Cl2((CH3)2NCH2CH2N(CH3)2) is significant in the field of organometallic chemistry and catalysis, particularly for its potential applications in polymerization reactions and as a catalyst in various chemical transformations. The structure of the compound is characterized by its ability to form strong π bonds with the phenyl groups and coordinate covalently with the chloride and bidentate ligands, which contributes to its stability and reactivity.

78067-99-9

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78067-99-9 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 78067-99-9 includes 8 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 5 digits, 7,8,0,6 and 7 respectively; the second part has 2 digits, 9 and 9 respectively.
Calculate Digit Verification of CAS Registry Number 78067-99:
(7*7)+(6*8)+(5*0)+(4*6)+(3*7)+(2*9)+(1*9)=169
169 % 10 = 9
So 78067-99-9 is a valid CAS Registry Number.

78067-99-9Downstream Products

78067-99-9Relevant academic research and scientific papers

ATTEMPTS TO PREPARE ALKYLIDENE ZIRCONIUM COMPLEXES BY α-HYDROGEN ATOM ABSTRACTION

Wengrovius, Jeffrey H.,Schrock, Richard R.

, p. 319 - 328 (1981)

We prepared several new neopentyl halide complexes of zirconium in order to test whether they could be induced to lose neopentane and give neopentylidene complexes by adding phosphorus or nitrogen donor ligands.ZrNp2X2 (X=Cl or Br) can be prepared in ether and isolated as a dietherate (an oil).It reacts with L (L=PMe3, PMe2Ph, NEt3, 1/2 DMPE, 1/2 TMEDA) to give ZrNp2X2L2.ZrNp3Cl can be prepared by adding MgNp2 to ZrNp2Cl2(ether)2 and isolated by sublimation in 25percent yield.On adding PMe3 or TMEDA, it disproportionates to ZrNp4 and ZrNp2Cl2L2.ZrCp''NpCl2 (Cp''=η5-C5Me5), ZrCp''Np2Cl, and ZrCp''Np3 were prepared by adding MgNp2 to ZrCp''Cl3.Only the last is a solid, only the first forms an adduct, ZrCp''NpCl2(PMe3).None of the complexes decomposed to tractable products in the presence of L.Photolysis of ZrNp2Cl2(PMe3)2 yielded 2 by an apparently complex reaction initiated by homolytic Zr-Np bond fission.

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