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81492-14-0

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81492-14-0 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 81492-14-0 includes 8 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 5 digits, 8,1,4,9 and 2 respectively; the second part has 2 digits, 1 and 4 respectively.
Calculate Digit Verification of CAS Registry Number 81492-14:
(7*8)+(6*1)+(5*4)+(4*9)+(3*2)+(2*1)+(1*4)=130
130 % 10 = 0
So 81492-14-0 is a valid CAS Registry Number.

81492-14-0Upstream product

81492-14-0Downstream Products

81492-14-0Relevant articles and documents

DARSTELLUNG UND SPECTROSKOPISCHE UNTERSUCHUNGEN VON METHYL- UND ISOPROPYLANTIMONHALOGENIDEN

Breunig, H. J.,Kanig, W.

, p. 149 - 160 (2007/10/02)

Halogenations of iPr3Sb yield the dihalides iPr3SbX2 X=Cl, Br, I.These compounds decompose thermally to iPrX and iPr2SbX.Halogenations of iPr2SbX produce unstable trihalides iPr2SbX3, which eliminate iPrX to give iPrSbX2.By this procedure only the bromides and iodides iPr2SbX and iPrSbX2 X=Br, I can be obtained in useful yields and purities.Pure iPrSbCl2 and iPr3Sb are products of exchange reaction of iPr2SbCl.The purity of the known methylcompounds Me2SbX X=Cl, Br, I obtained by decomposition of Me3SbX2 has been examined.MeSbI2 and Me3Sb are formed from Me2SbI.Previously unpublished ir-, 1H-nmr-, and ms-data of iPr3SbX2, R2SbX and RSbX2 R=Me, iPr, X=Cl, Br, I are discussed.

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