83705-83-3

Upstream product

• 82582-52-3 [IrH₂(C₆H₄BrI)(P(C₆H₅)3)2]⁽¹⁺⁾*BF₄^(1-)=[IrH₂(C₆H₄BrI)(P(C₆H₅)3)2]BF₄ 
• 38834-40-1 [Ir(1,5-COD)(P(C₆H₅)3)2]BF₄ 
• 82582-50-1 dihydrido(1,2-diiodobenzene)bis(triphenylphosphine)iridium(III) tetrafluoroborate 
• 82582-66-9 dihydridobis(triphenylphosphine)bis(iodomethane)iridium(III) tetrafluoroborate 

Relevant academic research and scientific papers

Iridium complexes of some halocarbons and the crystal and molecular structure of cis,trans-[IrH2(0-C6H4i2)(PPh 3)2]BF4

cts,cw,trans-[IrH2(Me2CO)2L 2]BF4 (L = PPh3) reacts with various halocarbons L/ which displace Me2CO to give cts,trans-[IrH2(L′)L2] (L′ = o-diiodobenzene and o-bromoiodobenzene). The crystal structure of the C6H4I2 complex was determined by X-ray methods. This complex crystallizes in the space group P2l/n with a = 13.309 (4) ?, b = 19.144 (4) ?, c = 16.317 (7) ?, β= 109.85 (3)°, and Z = 4. Full-matrix least-squares refinement using anisotropic thermal parameters for the iridium, phosphorus, iodine, and fluorine atoms and isotropic thermal parameters for the remaining atoms converged to the final residuals R1 = 0.047 and R2 = 0.050. The L′ ligand was found to chelate to iridium via the halogen groups. Other more weakly binding ligands such as C6H5I and RI (R = Me, Et, i-Pr) do not displace Me2CO, but analogous complexes can be obtained by hydrogenating [Ir(cod)L2]BF4 (cod = 1,5-cyclooctadiene) in the presence of the halocarbon. These have been detected by 1H NMR and in some cases isolated. Some analogues were obtained for L = PMePh2. The halo ligands were displaced by MeCN and displaced or partially displaced by EtOH (100 molar equiv).