86782-16-3 Usage
Uses
Used in Pharmaceutical Industry:
[(4E,6E,10E)-13,14,20,22-tetrahydroxy-17-methoxy-4,8,10,12,16-pentamethyl-3-oxo-2-azabicyclo[16.3.1]docosa-4,6,10,19,21,23-hexaen-9-yl] carbamate is used as a potential pharmaceutical compound for its possible biological activity. The presence of multiple hydroxyl and methoxy groups, along with the carbamate functional group, may contribute to its interaction with biological targets, making it a candidate for drug development.
Used in Chemical Research:
In the field of chemical research, [(4E,6E,10E)-13,14,20,22-tetrahydroxy-17-methoxy-4,8,10,12,16-pentamethyl-3-oxo-2-azabicyclo[16.3.1]docosa-4,6,10,19,21,23-hexaen-9-yl] carbamate can be used as a subject for studying the effects of its unique structural features on its chemical properties and reactivity. This may lead to the discovery of new synthetic methods or applications in various chemical processes.
Used in Material Science:
The highly conjugated system and the presence of multiple functional groups in [(4E,6E,10E)-13,14,20,22-tetrahydroxy-17-methoxy-4,8,10,12,16-pentamethyl-3-oxo-2-azabicyclo[16.3.1]docosa-4,6,10,19,21,23-hexaen-9-yl] carbamate make it a potential candidate for applications in material science. It could be investigated for its potential use in the development of new materials with specific properties, such as optical, electronic, or mechanical characteristics.
Check Digit Verification of cas no
The CAS Registry Mumber 86782-16-3 includes 8 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 5 digits, 8,6,7,8 and 2 respectively; the second part has 2 digits, 1 and 6 respectively.
Calculate Digit Verification of CAS Registry Number 86782-16:
(7*8)+(6*6)+(5*7)+(4*8)+(3*2)+(2*1)+(1*6)=173
173 % 10 = 3
So 86782-16-3 is a valid CAS Registry Number.
InChI:InChI=1/C28H40N2O8/c1-14-8-7-9-15(2)27(35)30-21-13-19(31)12-20(24(21)34)26(37-6)18(5)11-22(32)23(33)16(3)10-17(4)25(14)38-28(29)36/h7-10,12-14,16,18,22-23,25-26,31-34H,11H2,1-6H3,(H2,29,36)(H,30,35)/b8-7+,15-9+,17-10+