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(Bis-trimethylsilanyl-methyl)-methyl-diphenyl-phosphonium; iodide is a chemical with a specific purpose. Lookchem provides you with multiple data and supplier information of this chemical.

86952-10-5

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86952-10-5 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 86952-10-5 includes 8 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 5 digits, 8,6,9,5 and 2 respectively; the second part has 2 digits, 1 and 0 respectively.
Calculate Digit Verification of CAS Registry Number 86952-10:
(7*8)+(6*6)+(5*9)+(4*5)+(3*2)+(2*1)+(1*0)=165
165 % 10 = 5
So 86952-10-5 is a valid CAS Registry Number.

86952-10-5SDS

SAFETY DATA SHEETS

According to Globally Harmonized System of Classification and Labelling of Chemicals (GHS) - Sixth revised edition

Version: 1.0

Creation Date: Aug 17, 2017

Revision Date: Aug 17, 2017

1.Identification

1.1 GHS Product identifier

Product name (bis(trimethylsilyl)methyl)(methyl)diphenylphosphonium iodide

1.2 Other means of identification

Product number -
Other names -

1.3 Recommended use of the chemical and restrictions on use

Identified uses For industry use only.
Uses advised against no data available

1.4 Supplier's details

1.5 Emergency phone number

Emergency phone number -
Service hours Monday to Friday, 9am-5pm (Standard time zone: UTC/GMT +8 hours).

More Details:86952-10-5 SDS

86952-10-5Relevant academic research and scientific papers

Some phosphorus Derivatives

Eaborn, Colin,Retta, Negussie,Smith, J. David

, p. 905 - 910 (2007/10/02)

Treatment of Li with PPh2Cl gave the phosphine PPh2, which, in spite of the steric crowding caused by the silicon ligand, was readily converted into the phosphonium salts Ph2H>I and Ph2Me>I; the latter on heating gave the ylid MePh2PC(SiMe3)2.In methanol at room temperature the phosphine PPh2 readily loses one Me3Si group to give PPh2; the remaining Me3Si groups are lost successively, with decreasing ease, giving finally PPh2Me.These Si-C bond cleavages are catalysed by acid but inhibited by base, and it is suggested that the initial step is protonation of the phosphine.The quaternary salt Ph2Me>I successively loses its Me3Si groups very readily in methanol, ultimately to give I.

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