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936553-09-2

trans-[(C6F5)(Ph2P(CH2)7CH=CH2)2PtCl] is a chemical with a specific purpose. Lookchem provides you with multiple data and supplier information of this chemical.

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  • 936553-09-2 Structure

  • Basic information

    1. Product Name: trans-[(C6F5)(Ph2P(CH2)7CH=CH2)2PtCl]
    2. Synonyms: trans-[(C6F5)(Ph2P(CH2)7CH=CH2)2PtCl]
    3. CAS NO:936553-09-2
    4. Molecular Formula:
    5. Molecular Weight: 1018.43
    6. EINECS: N/A
    7. Product Categories: N/A
    8. Mol File: 936553-09-2.mol

  • Chemical Properties

    1. Melting Point: N/A
    2. Boiling Point: N/A
    3. Flash Point: N/A
    4. Appearance: N/A
    5. Density: N/A
    6. Refractive Index: N/A
    7. Storage Temp.: N/A
    8. Solubility: N/A
    9. CAS DataBase Reference: trans-[(C6F5)(Ph2P(CH2)7CH=CH2)2PtCl](CAS DataBase Reference)
    10. NIST Chemistry Reference: trans-[(C6F5)(Ph2P(CH2)7CH=CH2)2PtCl](936553-09-2)
    11. EPA Substance Registry System: trans-[(C6F5)(Ph2P(CH2)7CH=CH2)2PtCl](936553-09-2)

  • Safety Data

    1. Hazard Codes: N/A
    2. Statements: N/A
    3. Safety Statements: N/A
    4. WGK Germany:
    5. RTECS:
    6. HazardClass: N/A
    7. PackingGroup: N/A
    8. Hazardous Substances Data: 936553-09-2(Hazardous Substances Data)

936553-09-2 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 936553-09-2 includes 9 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 6 digits, 9,3,6,5,5 and 3 respectively; the second part has 2 digits, 0 and 9 respectively.
Calculate Digit Verification of CAS Registry Number 936553-09:
(8*9)+(7*3)+(6*6)+(5*5)+(4*5)+(3*3)+(2*0)+(1*9)=192
192 % 10 = 2
So 936553-09-2 is a valid CAS Registry Number.

936553-09-2Upstream product

936553-09-2Relevant articles and documents

Monophosphine and diphosphine ligands for diplatinum polyynediyl complexes: Efficient syntheses of new functionality-containing systems and model compounds

de Quadras, Laura,Stahl, Jürgen,Zhuravlev, Fedor,Gladysz, John A.

, p. 1859 - 1870 (2007)

Br(CH2)4Br and NaO(CH2)2CH{double bond, long}CH2 react under suitable conditions to give Br(CH2)4O(CH2)2CH{double bond, long}CH2 (55%), which is

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