98542-01-9Relevant academic research and scientific papers
Synthesis and stability study of a new bimetallic complex (Ph 3P)3CuMn(CO)5
Ahmad,Potratz,Qadir
, p. 1597 - 1599 (2013/05/22)
The present work deals with the preparation and stability study of new bimetallic compound related to hetero bimetallic complex (Ph3P) 3CuMn(CO)5. Mn2(CO)10 cleaved to KMn(CO)5 in the presence of Na/K alloy. CuCl and KMn(CO)5 reacted with triphenyl phosphine in the presence of THF at -78 °C. It yielded a mixture of (Ph3P)3CuCl and KMn(CO)5. At 0 °C, this mixture reacted and produced (Ph3P) 3CuMn(CO)5 and Ph3P. New product (Ph 3P)3CuMn(CO)5 was found very sensitive to oxidation. It decomposed into (Ph3P), Cu and Mn2(CO) 10 under vacuum, at room temperature. Copyright
Bimetallic complexes containing copper. The crystal structures of (tmed)CuMo(CO)3(η5-C5H5) and [(C6H5)3P]3CuV(CO)6
Doyle, Gerald,Eriksen, Kenneth A.,Van Engen, Donna
, p. 2201 - 2206 (2008/10/08)
The reaction of phosphine- or diamine-substituted copper(I) halides with various metal carbonyl anions leads to the formation of heteronuclear bimetallic complexes where one of the metals is copper. These complexes exhibit a wide range of Cu-M and Cu-CO interactions. (Ph3P)3CuV(CO)6, prepared from (Ph3P)2CuCl and Na(diglyme)2V(CO)6, exists as discrete trigonal planar (Ph3P)3Cu+ cations and octahedral V(CO)6- anions. The compound crystallizes in the triclinic space group P1 with a = 11.669 (1) ?, b = 12.691 (2) ?, c = 19.432 (2) ?, α = 102.17 (2)°, β = 92.03 (1)°, γ = 108.25 (1)°, and Z = 2. The structure was solved by heavy-atom techniques and refined by full-matrix least squares to R = 0.050 and Rw = 0.054. The LnCuM(CO)3(η5-C5H5) complexes (Ln = (Ph3P)2 or (CH3)2NCH2CH2N(CH3) 2; M = Cr, Mo, W) all appear to have a Cu-M bond with a single terminal and two semibridging carbonyl groups. (tmed)CuMo(CO)3(η5-C5H5) crystallizes in the monoclinic space group P21/n with a = 8.134 (1) ?, b = 14.632 (2) ?, c = 13.993 (2) ?, β = 94.76 (1)°, and Z = 4. The final residuals are R = 0.027 and Rw = 0.032.
