(1S,12S,14R)-9-methoxy-4,4-dimethyl-11-oxa-4-azoniatetracyclo[8.6.1.01,12.06,17]heptadeca-6(17),7,9,15-tetraen-14-ol;iodide

Base Information

Chemical Name:(1S,12S,14R)-9-methoxy-4,4-dimethyl-11-oxa-4-azoniatetracyclo[8.6.1.01,12.06,17]heptadeca-6(17),7,9,15-tetraen-14-ol;iodide
CAS No.:3891-74-5
Molecular Formula:C18H24INO3
Molecular Weight:429.298
Hs Code.:
Mol file:3891-74-5.mol

Synonyms:SCHEMBL3124708;AKOS030501884

Suppliers and Price of (1S,12S,14R)-9-methoxy-4,4-dimethyl-11-oxa-4-azoniatetracyclo[8.6.1.01,12.06,17]heptadeca-6(17),7,9,15-tetraen-14-ol;iodide

Supply Marketing:

Business phase:: The product has achieved commercial mass production^*data from LookChem market partment

Manufacturers and distributors:

Manufacture/Brand
Chemicals and raw materials
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Total 3 raw suppliers

Chemical Property of (1S,12S,14R)-9-methoxy-4,4-dimethyl-11-oxa-4-azoniatetracyclo[8.6.1.01,12.06,17]heptadeca-6(17),7,9,15-tetraen-14-ol;iodide

Chemical Property:

Hydrogen Bond Donor Count:1
Hydrogen Bond Acceptor Count:4
Rotatable Bond Count:1
Exact Mass:429.08009
Heavy Atom Count:23
Complexity:477

Purity/Quality:: 95%+ or 98%+ ^*data from raw suppliers

Safty Information:

Pictogram(s):
Hazard Codes:

MSDS Files:: SDS file from LookChem

Useful:

Canonical SMILES:C[N+]1(CCC23C=CC(CC2OC4=C(C=CC(=C34)C1)OC)O)C.[I-]
Isomeric SMILES:C[N+]1(CC[C@@]23C=C[C@@H](C[C@@H]2OC4=C(C=CC(=C34)C1)OC)O)C.[I-]

Technology Process of (1S,12S,14R)-9-methoxy-4,4-dimethyl-11-oxa-4-azoniatetracyclo[8.6.1.01,12.06,17]heptadeca-6(17),7,9,15-tetraen-14-ol;iodide

There total 3 articles about (1S,12S,14R)-9-methoxy-4,4-dimethyl-11-oxa-4-azoniatetracyclo[8.6.1.01,12.06,17]heptadeca-6(17),7,9,15-tetraen-14-ol;iodide which guide to synthetic route it. The literature collected by LookChem mainly comes from the sharing of users and the free literature resources found by Internet computing technology. We keep the original model of the professional version of literature to make it easier and faster for users to retrieve and use. At the same time, we analyze and calculate the most feasible synthesis route with the highest yield for your reference as below:

synthetic route:

Reference yield: 99.0%