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106420-40-0

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106420-40-0 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 106420-40-0 includes 9 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 6 digits, 1,0,6,4,2 and 0 respectively; the second part has 2 digits, 4 and 0 respectively.
Calculate Digit Verification of CAS Registry Number 106420-40:
(8*1)+(7*0)+(6*6)+(5*4)+(4*2)+(3*0)+(2*4)+(1*0)=80
80 % 10 = 0
So 106420-40-0 is a valid CAS Registry Number.

106420-40-0Upstream product

106420-40-0Relevant articles and documents

Preparation and reaction chemistry of trimethylsilyl derivatives of niobium. Redox chemistry of (η5-C5H5)2Nb(SiMe3)Cl and x-ray structures of (η5-C5H5)2Nb(SiMe 3)(η2-C2H4) and [(η5-C ...

Arnold, John,Don Tilley,Rheingold, Arnold L.,Geib, Steven J.

, p. 473 - 479 (2008/10/08)

Full title: Preparation and reaction chemistry of trimethylsilyl derivatives of niobium. Redox chemistry of (η5-C5H5)2Nb(SiMe3)Cl and x-ray structures of (η5-C5H5)2Nb(SiMe 3)(η2-C2H4) and [(η5-C5H5)2Nb(CH 2SiMe3)Cl]PF6. The purple niobium(IV) silyl complex (η5-C5H5)2Nb(SiMe3)Cl (1) is prepared from reaction of (η5-C5H5)2NbCl2 with Hg(SiMe3)2. Reduction of 1 in the presence of ligands (L) affords niobium(III) silyl complexes (η5-C5H5)2Nb(SiMe 3)(L), where L = CO, PMe3, and C2H4. (η5-C5H5)2Nb(SiMe 3)(η2-C2H4) (4) crystallizes in the orthorhombic space group Pnma with a = 13.756 (3) A?, b = 12.819 (3) A?, c = 8.541 (2) A?, Z = 4, and RF = 2.26%. A crystallographic mirror plane in 4 contains the niobium atom, the ethylene ligand, Si, and C(9). The Nb-Si distance is 2.669 (1) A?. Oxidation of 1 in dichloromethane with ferrocenium hexafluorophosphate results in a complex reaction that produces Me3SiCl, Me3SiF, [(η5-C5H5)2Nb-(CH 2SiMe3)Cl]PF6 (5), and [(η5-C5H5)2NbCl 2]PF6 (6). The methylene group in 5 originates from the dichloromethane solvent. The mechanism of this reaction is discussed. Crystals of 5 are orthorhombic, space group P212121, with a = 10.542 (2) A?, b = 12.546 (2) A?, c = 14.712 (2) A?, Z = 4, and RF = 4.11%. The Nb-C σ bond distance in 5 is 2.208 (8) A?.

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