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1272-71-5

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1272-71-5 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 1272-71-5 includes 7 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 4 digits, 1,2,7 and 2 respectively; the second part has 2 digits, 7 and 1 respectively.
Calculate Digit Verification of CAS Registry Number 1272-71:
(6*1)+(5*2)+(4*7)+(3*2)+(2*7)+(1*1)=65
65 % 10 = 5
So 1272-71-5 is a valid CAS Registry Number.

1272-71-5SDS

SAFETY DATA SHEETS

According to Globally Harmonized System of Classification and Labelling of Chemicals (GHS) - Sixth revised edition

Version: 1.0

Creation Date: Aug 20, 2017

Revision Date: Aug 20, 2017

1.Identification

1.1 GHS Product identifier

Product name bis(mesitylene)vanadium(0)

1.2 Other means of identification

Product number -
Other names -

1.3 Recommended use of the chemical and restrictions on use

Identified uses For industry use only.
Uses advised against no data available

1.4 Supplier's details

1.5 Emergency phone number

Emergency phone number -
Service hours Monday to Friday, 9am-5pm (Standard time zone: UTC/GMT +8 hours).

More Details:1272-71-5 SDS

1272-71-5Relevant articles and documents

Bis(arene)vanadium anions: A new class of organovanadium complexes. X-ray structural characterization of solvated K[(η6-1,3,5-C6H3Me3) 2V]

Fochi, Giovanni,Braga, Dario,Sabatino, Piera

, p. 565 - 566 (2008/10/08)

Reduction of bis(η6-arene)vanadium(0) complexes with potassium gives the corresponding bis(η6-arene)vanadium(-I) derivatives (arene = C6H6, 1,3,5-C6H3Me3) as their K+ salts. A single-crystal diffraction study of solvated K[(η6-1,3,5-C6H3Me3) 2V] shows that the anion presents two different rotameric configurations in the solid, though the sandwich structure is preserved, and that contact ion pairs are established with the K+ cations, which also interact with THF and dioxane solvent molecules. Crystal data: monoclinic, space group P21, a = 10.213 (2) A?, b = 18.518 (3) A?, c = 13.402 (3) A?, β = 89.58 (1)°, V = 2534.6 A?3, and Z = 4.

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