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{(2-diphenylphosphino)phenoxo-OP}{(2-hydroxyphenyl)diphenylphosphine}(η-pentamethylcyclopentadienyl)ruthenium(II)}2 is a chemical with a specific purpose. Lookchem provides you with multiple data and supplier information of this chemical.

128569-71-1

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128569-71-1 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 128569-71-1 includes 9 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 6 digits, 1,2,8,5,6 and 9 respectively; the second part has 2 digits, 7 and 1 respectively.
Calculate Digit Verification of CAS Registry Number 128569-71:
(8*1)+(7*2)+(6*8)+(5*5)+(4*6)+(3*9)+(2*7)+(1*1)=161
161 % 10 = 1
So 128569-71-1 is a valid CAS Registry Number.

128569-71-1Downstream Products

128569-71-1Relevant articles and documents

Half-sandwich Ruthenium Complexes of a P-O Bifunctional Ligand. X-Ray Crystal Structure of >

Canestrari, Massimo,Chaudret, Bruno,Dahan, Francoise,Huang, Yong-Shen,Poilblanc, Rene,et al.

, p. 1179 - 1182 (1990)

The reaction of the phosphine PPh2(C6H4OH) with a reduced solution of n> (1) by zinc in methanol produces > (4).This complex crystallizes in the monoclinic system, space group P21/c, with a = 11.070(1), b = 18.582(2), c = 19.393(2) Angstroem, and β = 106.05(1) deg and was refined to R = 0.028 with 4 383 reflections having (F02) > 3?(F02).The X-ray structure shows the compound to exhibit strong hydrogen bonding between the hydroxyl proton of the phosphine and the oxygen group of the chelating phenoxy diphenylphosphine ligand .Compound (4) is unreactive towards H2, NaBH4, LiBHEt3, CF3CO2H, and MeI probably because of electronic and co-ordinative saturation.Reaction of the hydroxyphosphine with 4> followed by addition of NEt3 leads to an insoluble solid (5) of the same composition as (4) but proposed to be oligomeric.Compound (5) is again unreactive except with HBF4*Et2O in the presence of which it decomposes.Reaction of PPh2(C6H4OSiMe3) with a reduced solution of (1) in methanol affords > (6) whereas addition of PPh2(C6H4OH) to (1) followed by reduction with NaBH4 in ethanol affords the trihydride > (8).

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