14970-07-1Relevant articles and documents
Reactivity patterns and catalytic chemistry of iridium polyhydride complexes
Goldman, Alan S.,Halpern, Jack
, p. 237 - 253 (2007/10/02)
(1, P=PPri3) reacts autocatalytically with CF3COOR (R=CH2CF3) in cyclo-C6D12 at 60 deg C according to: 1 + CF3COOR -> (2) + ROH (4) (eq.1).The rate-law, -d/dt=k1/21/2-1/2 (k=1.25*10-4 M-1/2 sec-1), is consistent with the mechanism, 1 + 2 2 (5) + 4 (rapid equilibrium); 5 + CF3COOR -> > (6) (rate determining); 6 -> 2 + CF3CHO; 5 + CF3CHO -> 2. 2 reacts rapidly with H2 (25 deg C, 1 atm) according to: 2 + 2H2 -> 1 + 4 (eq.2).Although the combination of reactions 1 and 2 constitute a catalytic cycle for the hydrogenation of CF3COOR (CF3COOR + 2H2 -> 2 (4), catalyzed by 1), such catalytic hydrogenation does not occur, presumably because H2 suppresses reaction by rapidly converting the catalytic intermediates, 2 and 5, to 1.However, 1 was found to be effective as a catalyst or catalyst precursor for transfer hydrogenation, e.g.CH2=CHC(CH3)3 + (CH3)2CHOH -> CH3CH2C(CH3)3 + (CH3)2C=O.While not directly detected, IrH3P2 could be trapped at low temperatures by N2 to yield the complexes and which are related through the labile equilibrium, + N2 2 (Keq ca. 1.5 at 35 deg C).
Alkyl halide transfer from palladium(IV) to platinum(II) and a study of reactivity, selectivity, and mechanism in this and related reactions
Aye, Khin-Than,Canty, Allan J.,Crespo, Margarita,Puddephatt, Richard J.,Scott, John D.,Watson, Andrew A.
, p. 1518 - 1522 (2008/10/08)
Kinetic studies of the oxidative addition of MeI or PhCH2Br to [MMe2(L2)] (M = Pd or Pt, L2 = 2,2′-bipyridine or 1,10-phenanthroline) indicate that the reactions occur by the SN2 mechanism, and the reactions occur 7-22 times faster when M = Pt over Pd and 1.2-2.2 times faster when L2 = phen over bpy. Reductive elimination from [PdBrMe2(CH2Ph)(L2)] in the solid state occurs to give both Me-Me and PhCH2Me, and there is a preference for methyl group loss. Thermochemical studies indicate that CH3-CH3 loss gives ΔH = -108 ± 4 kJ mol-1 but PhCH2-CH3 loss gives ΔH = -48 ± 12 kJ mol-1, indicating a relatively strong PhCH2-Pd bond. The complexes [PdIMe3(L2)] or [PdBrMe2(CH2Ph)(L2)] react rapidly with [PtMe2(L2)] by alkyl halide transfer. Kinetic studies have shown that the major route involves loss of halide from palladium(IV) in a preequilibrium step, followed by SN2 attack by [PtMe2(L2)] on an alkyl group of [PdMe3(L2)]+ or [PdMe2(CH2Ph)(L2)]+. In the latter case, benzyl group transfer is preferred over methyl group transfer.