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1589-07-7

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1589-07-7 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 1589-07-7 includes 7 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 4 digits, 1,5,8 and 9 respectively; the second part has 2 digits, 0 and 7 respectively.
Calculate Digit Verification of CAS Registry Number 1589-07:
(6*1)+(5*5)+(4*8)+(3*9)+(2*0)+(1*7)=97
97 % 10 = 7
So 1589-07-7 is a valid CAS Registry Number.

1589-07-7Relevant articles and documents

Allylstannation X. Stereochemical course of the Addition Reactions of (E/Z)-Bu3SnCH2CH=CHCH3 with Aldehydes in the Presence of Lewis Acids (Bu2SnCl2, BF3.Et2O, and TiCl4)

Boaretto, Andrea,Marton, Daniele,Tagliavini, Giuseppe,Ganis, Paolo

, p. 199 - 208 (1987)

Reactions between (E/Z)-Bu3SnCH2CH=CHCH3 and RCHO (R= CH3, C2H5, n-C3H7, n-C4H9, n-C5H11, (CH3)2CH, (CH3)3C, C6H5, CH2=CH, CH2=C(CH3), (E)-CH3CH=CH, (E)-C3H7CH=CH, (E)-C6H5CH=CH) have been carried out in the presence of Lewis acids such as Bu2SnCl2, BF3.Et2O, and TiCl4.The stereochemical course of the reactions to give homoallylic alcohols does not necessarily depend on the formation of intermediate Lewis acid-aldehyde complexes, but rather upon the formation of allylmetal compounds (e.g.Bu2ClSnCH2CH=CHCH3, Bu2ClSnCH(CH3)CH=CHCH2, Cl3TiCH2CH=CHCH3, etc.) which are the actual species which react with the carbonyl compounds.Bu3SnCH2CH=CHCH3 does not undergo the reaction.

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