193694-04-1 Usage
Uses
Used in Organic Synthesis:
4-BROMO-1-(TERT-BUTYLDIMETHYLSILYL)INDOLE is used as a protected intermediate in organic synthesis for the preparation of various indole-based compounds. The bromine atom attached to the structure allows for further functionalization through halogenation reactions, while the tert-butyldimethylsilyl group protects reactive functional groups during the synthesis process.
Used in Pharmaceutical Industry:
In the pharmaceutical industry, 4-BROMO-1-(TERT-BUTYLDIMETHYLSILYL)INDOLE is used as a building block for the development of indole-based drugs. Its unique structure and reactivity make it a valuable component in the synthesis of bioactive molecules with potential therapeutic applications.
Used in Chemical Research:
4-BROMO-1-(TERT-BUTYLDIMETHYLSILYL)INDOLE is utilized as a research compound in chemical studies, particularly in the investigation of indole chemistry, halogenation reactions, and the protective role of silyl groups in organic synthesis. Its unique properties and reactivity provide valuable insights into the development of new synthetic methods and strategies.
Used in Material Science:
In material science, 4-BROMO-1-(TERT-BUTYLDIMETHYLSILYL)INDOLE may be employed as a precursor for the synthesis of novel materials with specific properties, such as optoelectronic materials, sensors, or catalysts. Its unique structure and reactivity can contribute to the development of advanced materials with potential applications in various fields.
Check Digit Verification of cas no
The CAS Registry Mumber 193694-04-1 includes 9 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 6 digits, 1,9,3,6,9 and 4 respectively; the second part has 2 digits, 0 and 4 respectively.
Calculate Digit Verification of CAS Registry Number 193694-04:
(8*1)+(7*9)+(6*3)+(5*6)+(4*9)+(3*4)+(2*0)+(1*4)=171
171 % 10 = 1
So 193694-04-1 is a valid CAS Registry Number.
InChI:InChI=1/C14H20BrNSi/c1-14(2,3)17(4,5)16-10-9-11-12(15)7-6-8-13(11)16/h6-10H,1-5H3