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mer-(Ph4As)[Ru(NO)Cl3(acetylacetonate)] is a chemical with a specific purpose. Lookchem provides you with multiple data and supplier information of this chemical.

194938-17-5

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194938-17-5 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 194938-17-5 includes 9 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 6 digits, 1,9,4,9,3 and 8 respectively; the second part has 2 digits, 1 and 7 respectively.
Calculate Digit Verification of CAS Registry Number 194938-17:
(8*1)+(7*9)+(6*4)+(5*9)+(4*3)+(3*8)+(2*1)+(1*7)=185
185 % 10 = 5
So 194938-17-5 is a valid CAS Registry Number.

194938-17-5Downstream Products

194938-17-5Relevant academic research and scientific papers

One-electron oxidation behavior of {MNO}6-type nitrosyl complexes having acetylacetonato ligand, [M(NO)Cl5-2n(acac)n]m (M=Ru, Os; N=1, 2; Acac=acetylacetonato)

Ooyama, Dai,Nagao, Noriharu,Nagao, Hirotaka,Sugimoto, Yuko,Howell, F. Scott,Mukaida, Masao

, p. 45 - 52 (1997)

The electrochemical behavior of several complexes with the general formula [M(NO)Cl5-2n(acac)n]m (M=Ru, Os; n=1, 2; acac=acetylacetonato) was investigated: mer-[Ru(NO)Cl3(acac)]- (1, n=1), cis-[Ru(NO)Cl(acac)2] (2, n=2), mer-[Os(NO)Cl3(acac)]- (3, n=1), cis-[Os(NO)Cl(acac)2] (4, n=2). The study includes the known corresponding n=0 complexes, [M(NO)Cl5]2- (M=Ru, Os), for comparison. All these complexes undergo a one-electron oxidation, which is rather unusual redox behavior in the {MNO}6-type nitrosyl complexes. The behavior of some of these complexes as electrophiles was also described. Molecular structures with a meridional configuration were established for the n=1 complexes ([Ru(NO)Cl3(acac)]- (1) and [Os(NO)Cl3(acac)]- (3)) by X-ray structure determinations. Crystal data for 1 (Bu4N salt): C21H43N2O3Cl3Ru, a=31.443(9), b=21.86(1), c=19.852(6) A, β=119.65(2)°, monoclinic, C2/c, Z=16. Crystal data for 3 (Cs salt): C5H7NO3Cl3OsCs, a=7.942(1), b=12.602(2), c=7.451(2) A, α=105.91(2), β=98.20(2), γ=90.31(1)°, triclinic, P1, Z=2.

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