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32356-70-0

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32356-70-0 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 32356-70-0 includes 8 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 5 digits, 3,2,3,5 and 6 respectively; the second part has 2 digits, 7 and 0 respectively.
Calculate Digit Verification of CAS Registry Number 32356-70:
(7*3)+(6*2)+(5*3)+(4*5)+(3*6)+(2*7)+(1*0)=100
100 % 10 = 0
So 32356-70-0 is a valid CAS Registry Number.

32356-70-0Relevant academic research and scientific papers

ELECTROCHEMISTRY OF COORDINATION COMPOUNDS. XX. ELECTROGENERATED Rh(CO)(PPh3)3 AND Ir(CO)(PPh3)3

Zotti, Gianni,Zecchin, Sandro,Pilloni, Giuseppe

, p. 61 - 72 (1983)

The redox behaviour of the d8 complexes + (M=Rh, Ir) was studied on platinum electrode in 1,2-dimethoxyethane by cyclic voltammetry, differential pulse voltammetry, and potentiostatic coulometry.The complexes show two reversible one-electron reductions consistent with the formation of the rare zerovalent M(CO)(PPh3)3 and the anionic - derivatives, respectively.The reduced species were characterized by ESR and IR spectroscopy.A significant feature is that the one-electron reduced intermediates, in spite of their radical nature, react very easily with molecules capable of reacting as proton rather than H-atom sources to give the hydride species HM(CO)(PPh3)3.A tentative interpretation of this behaviour is suggested.

Displacement of hard bases from a soft center by a soft ligand: Reaction of Ir(CO)(OH)(SO4)L2 (L = PPh3, P(p-tolyl)3) with CO and the crystal structure of [Ir(CO)3PPh3]2+[HSO4 -]·1/3H2O

Randall, Sherri L.,Thompson, Jeffrey S.,Buttrey, Lisa A.,Ziller, Joseph W.,Churchill, Melvyn Rowen,Atwood, Jim D.

, p. 683 - 688 (2008/10/08)

The iridium(III) complexes Ir(CO)(OH)(SO4)L2, L = PPh3, P(p-tolyl)3, have been prepared and shown to react with CO, yielding the iridium(I) species [Ir(CO)3L2+][HSO4-] (L = PPh3, P(p-tolyl)3) and CO2. The species [Ir(CO)3(PPh3)2+][HSO 4-]·1/3H2O crystallizes in the centrosymmetric rhombohedral space group R3 [C3i2; No. 148]. Cell parameters (for the hexagonal setting) are a = 40.938 (7) A?, c = 11.850 (2) A?, V = 17199 A?3, and Z = 18. Diffraction data (Mo Kα?, 2θ = 4.0-45.0°) were collected on a Syntex P21 diffractometer, and the structure was refined to RF = 6.1% for all 4772 unique data (RF = 4.2% for those 3673 data with |Fo| > 6.0σ (|Fo|)).

Carbonylation of metal-oxygen bonds. Formation of carbalkoxydicarbonylbis(triphenylphosphine)iridium, ROC(O)Ir(CO)2(PPh3)2, by carbonylation of trans-alkoxycarbonylbis(triphenylphosphine)iridium, trans-ROIr(CO)(PPh3)2 (R = Me, n-Pr, Ph)

Rees, Wayne M.,Atwood, Jim D.

, p. 402 - 404 (2008/10/08)

Carbonylation of the complexes trans-MeOIr(CO)(PPh3)2, trans-(n-PrO)Ir(CO)(PPh3)2, and trans-PhOIr(CO)(PPh3)2 leads to carboalkoxy complexes ROC-(O)Ir(CO)2(PPh3)2 in high yield. Identification of the intermediate Ir(CO)3(PPh3)2+ OR- indicates a two-step mechanism - first displacement of the alkoxide from the coordination sphere and then nucleophilic attack on a carbon of the cationic carbonyl complex. The hydroxy complex did not undergo carbonylation under similar conditions.

Reactions involving Transition Metals. Part 15. Reactions of Alkyl an Acyl-peroxy-anions with (1+) (M= Ir or Rh)

Bird, Christopher,Booth, Brian L.,Haszeldine, Robert N.

, p. 517 - 522 (2007/10/02)

The title compounds react with peroxycarboxylic acids RCO3H in the presence of NEt3 to give the compounds (L = PPh3), which, with MeI, give and (R = C6H4Cl-m, Ph, or Me).Reaction between NaO2COR' (R' = C6H4Cl-m) and (1+) affords an inseparable mixture of , , and ; under similar conditions the rhodium analogue gives a mixture of and .Reactions between NaO2But and either (1+) or give only .

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