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6181-08-4

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6181-08-4 Usage

Uses

Ethyl-2-d1 Alcohol (CAS# 6181-08-4) is a useful isotopically labeled research compound.

Check Digit Verification of cas no

The CAS Registry Mumber 6181-08-4 includes 7 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 4 digits, 6,1,8 and 1 respectively; the second part has 2 digits, 0 and 8 respectively.
Calculate Digit Verification of CAS Registry Number 6181-08:
(6*6)+(5*1)+(4*8)+(3*1)+(2*0)+(1*8)=84
84 % 10 = 4
So 6181-08-4 is a valid CAS Registry Number.
InChI:InChI=1/C17H17FN2O4/c1-2-3-10-24-14-7-4-12(5-8-14)17(21)19-13-6-9-15(18)16(11-13)20(22)23/h4-9,11H,2-3,10H2,1H3,(H,19,21)

6181-08-4SDS

SAFETY DATA SHEETS

According to Globally Harmonized System of Classification and Labelling of Chemicals (GHS) - Sixth revised edition

Version: 1.0

Creation Date: Aug 15, 2017

Revision Date: Aug 15, 2017

1.Identification

1.1 GHS Product identifier

Product name 4-butoxy-N-(4-fluoro-3-nitrophenyl)benzamide

1.2 Other means of identification

Product number -
Other names 2-Deuterio-ethanol-1

1.3 Recommended use of the chemical and restrictions on use

Identified uses For industry use only.
Uses advised against no data available

1.4 Supplier's details

1.5 Emergency phone number

Emergency phone number -
Service hours Monday to Friday, 9am-5pm (Standard time zone: UTC/GMT +8 hours).

More Details:6181-08-4 SDS

6181-08-4Downstream Products

6181-08-4Relevant articles and documents

Bioconversion of D-glucose in heavy water: Effect of water isotopomeric composition on deuterium fragment distribution in ethanol

Sakhabutdinov,Bisikalo,Kushnarev,Rokhin,Kulagina

experimental part, p. 2058 - 2061 (2011/05/07)

The relative distribution of deuterium between methyl and methylene groups in ethanol at the bioconversion of D-glucose in heavy water was studied.

Metastable Decompositions of C5H10O+. Ions with the Oxygen on the Middle Carbon: A Test for Energy Randomization

McAdoo, David J.,Farr, William,Hudson, Charles E.

, p. 5165 - 5169 (2007/10/02)

This study was undertaken to define the mechanisms of metastable decomposition of C5H10O+. ions with the oxygen on the middle carbon, and to test the assumption that internal energy becomes randomly distributed prior to the unimolecular decompositions of gaseous ions.CH3CH2C(=OH+)CH2CH2. (2), CH3CH2C(=OH+).CHCH3 (3), and CH3CH2C(OH+.)HCH=CH2 (4) all rearrange to CH3CH2C(=O+.)CH2CH3 (1) prior to metastable decomposition.However, 2 - 4 lose ethyl 50 - 100 times as often as they lose ethane following rearrangement to 1, while 1 formed by ionization of 3-pentanone loses exclusively ethane.These differences are attributed to excess energy in the isomerized ions. 3-Pentanone ions formed by isomerization of 2 - 4 lose ethyl and ethane from opposite sides at unequal rates, possibly owing to incomplete randomization of energy following isomerization.

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