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C2H5CH2CH2CHCHCHCH3Cl is a chemical with a specific purpose. Lookchem provides you with multiple data and supplier information of this chemical.

66873-69-6

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66873-69-6 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 66873-69-6 includes 8 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 5 digits, 6,6,8,7 and 3 respectively; the second part has 2 digits, 6 and 9 respectively.
Calculate Digit Verification of CAS Registry Number 66873-69:
(7*6)+(6*6)+(5*8)+(4*7)+(3*3)+(2*6)+(1*9)=176
176 % 10 = 6
So 66873-69-6 is a valid CAS Registry Number.

66873-69-6Downstream Products

66873-69-6Relevant academic research and scientific papers

Comparison of the allylation reactions of aldehydes using allylstannanes with boron trifluoride etherate and boron trichloride

Marton, Daniele,Tagliavini, Giuseppe,Zordan, Michele,Wardell, James L.

, p. 127 - 138 (2007/10/02)

Reactions between allylstannanes, R2CH=CHCHR1SnBu3 (R1 = R2 = H (4); R1 = H, R2 = Me (5); R1R2 = (CH2)3 (6) and aldehydes, RCHO (e.g.R = Et) in the presence of BF3OEt2 in CH2Cl2 at -78 deg C produce stereoselectively erythro-RCH(OH)CHR2CH=CHR1 (with one equivalent RCHO) and 4-OH-3-R1-5-R2-2,6-R2-tetrahydropyrans (with an excess of RCHO).In contrast, when BCl3 is used in place of BF3OEt2 the reactions give mixtures of chlorinated alkenes (both homoallyl chlorides and allyl chlorides) and 4-Cl-3-R1-5-R2-2,6-R2-tetrahydropyrans (3; X = Cl).Thus 5, EtCHO and BCl3 (all equimolar) provide EtCHClCH2CH=CHMe (51percent, (E) + (Z)), EtCHClCHMeCH=CH2 (7percent, erythro + threo), EtCH2CH=CH-CHMeCl (30percent, (E) + (Z)) and 3 (12percent, X = Cl); with EtCHO (2.2 equivalents). 3 (X = Cl; cis/trans = 70/30) becomes the sole product.The product, erythro-EtCHClCHCH=CH(CH2)2CH2 (97percent) was produced from equimolar EtCHO, BCl3 and 6; with excess EtCHO (2.2 equivalents), 9-Cl-2,4-Et2-cis-3-oxabicyclononane (17percent; cis/trans = 45/55) and erythro-EtCHClCHCH=CH(CH2)2CH2 (78percent) were obtained.

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