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92695-35-7

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92695-35-7 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 92695-35-7 includes 8 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 5 digits, 9,2,6,9 and 5 respectively; the second part has 2 digits, 3 and 5 respectively.
Calculate Digit Verification of CAS Registry Number 92695-35:
(7*9)+(6*2)+(5*6)+(4*9)+(3*5)+(2*3)+(1*5)=167
167 % 10 = 7
So 92695-35-7 is a valid CAS Registry Number.

92695-35-7Relevant articles and documents

Syntheses and structures of ?-pyridine, quinoline, and isoquinoline complexes of the formula 5-C5H5)Re(NO)(PPh3)(NCxHy)>+ CF3SO3-

Dewey, Michael A.,Arif, Atta M.,Gladysz, J. A.

, p. C29 - C32 (1990)

Reaction of (η5-C5H5)Re(NO)(PPh3)(OTf) with pyridine, quinoline, and isoquinoline gives the title complexes in high yields.The crystal structure of the isoquinoline complex is determined, and exhibits unexpected features.

Synthesis and reactivity of chiral metal fluoride and water complexes derived from the rhenium fragment [(η5-C5H5)Re(NO) (PPh3)]+

Agbossou, Sénamé K.,Roger, Christophe,Igau, Alain,Gladysz

, p. 419 - 424 (2008/10/08)

Reactions of triflate complex (η5-C5H5)Re(NO)(PPh3)(OTf) (6), chlorobenzene complex [(η5-C5H5)Re(NO)(PPh3)-(ClC 6H5)]+BF4-, and tetrahydrofuran complex [(η5-C5H5)Re(NO)(PPh 3)(THF)]+BF4- with (Me2N)3S+[SiMe3F2] - give fluoride complex (η5-C5H5)Re(NO)(PPh3)(F) (3) in ≥95% NMR yields. Analytically pure 3 can be isolated from the last reaction in 65-75% yields, but decomposes on the time scale of hours in solution. The reaction of 3 with BF3·OEt2 (-95 to -40°C) gives the dichloromethane complex [(η5-C5H5)Re(NO)(PPh3)(ClCH 2Cl)]+BF4- (1), and that with MeOTf gives 6 and MeF. Reaction of 3 and P(p-tol)3 gives mainly the fluoride ligand substitution product [(η5-C5H5)Re(NO)(PPh 3)(P(p-tol)3)]+X-. Reaction of 1 and H2O gives the water complex [(η5-C5H5)Re(NO)(PPh3)(OH 2)]+BF4- (4+BF4-, 87%), which in turn reacts with CH3CN (3 equiv) to give [(η5-C5H5)Re(NO)(PPh3)(NCCH 3)]+BF4- and H2O. Reaction of (η5-C5H5)Re(NO)(PPh3)(H) with Ph3C+PF6- and then H2O gives 4+PF6- (91%). Reaction of (η5-C5H5)Re(NO)(PPh3)(CH 3) and aqueous HF appears to give water complex 4+X- (X- = F- or HF2-). Complex 3 is inert to water, but converts to 4+X- in the presence of HF or HBF4·OEt2.

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