2786 Organometallics, Vol. 24, No. 11, 2005
Matsumoto and Espenson
their polarity; dielectric constants are as follows: ben-
zene, 2.28; chloroform, 4.72; acetone, 20.7; acetonitrile,
35.95.36 The rate laws with D ) phenol-d6 and B ) Lut
in each solvent were interpreted according to the
relative values of terms in the denominator of eq 16:
i.e., k-2 . k3[D] in benzene-d6; k-2 ≈ k3[D] in chloroform-
d; k-2 , k3[D] in acetone-d6 or acetonitrile-d3. Although
the solvent dependence of the rate law does not allow a
rigorous comparison of the rate constants among all
solvents, the general trend indicates the accelerating
effect of polar solvents. The faster reactions observed
in more polar solvents suggest the intervention of
charged or polarized intermediates. In a polar solvent
such as acetonitrile-d3, enolate-MTO might be produced
by the deprotonation of MTO, whereas the partial
deprotonation of MTO or the formation of a strong ion
pair {[CH2dReO3]-‚[HB]+} might be favored in nonpolar
solvents because charged species are substantially
destabilized by the lack of solvation.15,41,43
Solvent effects on the basicity of the bases toward a
proton in MTO should also be considered.42 The ratio
of the equilibrium constants for the deprotonation
process in benzene-d6 is K1K2(Lut)/K1K2(MeQ) ) 4.4.
The ratio of the rate constants for the deprotonation
process in acetone-d6 is K1k2(Lut)/K1k2(MeQ) ) 3.9. (The
ratio of K1k2 strongly reflects the deprotonation process,
because acid/base neutralization reaction is rapid.) This
ratio can be compared with the ratio of Ka in water:
Ka(LutH+)/Ka(MeQH+) ) 6. The rough agreement indi-
cates solvent effects on the basicity of bases are rela-
tively small and the partial proton extraction from MTO
occurs in both benzene-d6 and acetone-d6.
Donor Effects. The H/D exchange rate diminishes
with increasing pKa of the deuterium donor: phenol
(9.99) > cresol (10.29) . methanol (15) . acetone (19).
Acetone-d6, a potential deuterium donor, did not ex-
change.
One might suspect that high concentrations of the
deuterium donors would alter the dielectric constant of
benzene-d6 solutions. The activity coefficient of the
proton and deuteron in a nonpolar solvent is likely to
be increased by the addition of polar reagents such as
phenol-d6 (ꢀ ) 12). To explore this matter, isodielectric
measurements were carried out by adding benzyl alco-
hol (ꢀ ) 10) at a concentration, together with phenol-
d6, such that [benzyl alcohol] + [phenol-d6] ) 1.3 mol
kg-1. The experiment failed, however, because benzyl
alcohol itself seems to coordinate to MTO, thus reducing
the H/D exchange reactivity.
their experimental errors, this can be taken as good
agreement. Thus, k3 directly reflects the heterolytic
O-D bond energy of phenol-d6 and o-cresol-d8.
The value K1K2k3 for D ) methanol-d4 can be also
calculated from the separately estimated K1K2 and k3.
The value 103K1K2k3(methanol-d4/Lut) ) 1.0 kg2 mol-2
s-1 is close to 103K1K2k3(o-cresol-d8/Lut) ) 1.2 kg2 mol-2
s-1, despite their pKa difference. Because methanol-d4
is as polar (ꢀ ) 32.6) as acetonitrile, methanol-d4 in the
bulk, which is 60 times in excess of MTO, may stabilize
the intermediates by specific solvation.
Reaction Coordinate Diagram. In this study, we
found that H/D exchange depends on the solvents, bases,
and deuterium donors. The formation of partially de-
protonated MTO as the intermediate is facilitated by a
strong Brønsted base. The pKa of a deuterium donor will
directly affect the activation barrier of H/D exchange.
The solvent may affect both the stability of the inter-
mediate and the activation barrier for H/D exchange.
Because H/D exchange directly reflects the pKa of the
deuterium donor, a lower activation barrier is expected
in polar solvents compared with that in nonpolar
solvents.
A reaction coordinate diagram of H/D exchange for
MTO is illustrated in Scheme 3; obviously it is nearly
symmetric for H/D exchange. In the beginning MTO
exists exclusively in the keto form because of the large
energy difference between keto- and enol-MTO. A base
present in solution interacts with MTO at the Re center
or at the methyl proton. Without steric hindrance, the
base interacts with the Re center of MTO to form a
trigonal-bipyramidal compound, which prevents keto/
enol tautomerization and, therefore, H/D exchange. A
base with a steric barrier initially interacts with MTO
at the methyl proton to form intermediate I1 with the
weakened C-H bond. This partial deprotonation of
MTO facilitates its keto/enol tautomerization. The
base-promoted enol isomer I2 or the strong ion pair
{[CH2dReO3]-‚[BH]+} is a reactive intermediate for
subsequent H/D exchange. The H/D exchange takes
place via an interaction between I2 and the deuterium
donor to form the activated complex. In Scheme 3 we
depicted the activated complex, which still requires the
old O-H/O-D bonds to break and the new O-D/O-H
bonds to form. Clearly, the heterolytic O-D bond energy
of a deuterium donor has a strong influence in this
process; however, the stability and reactivity of I2 also
depend on the nature of a base and a solvent. The
sequence as written contains several rapid steps that
have been postulated; not every one was capable of
independent verification. The deuterated intermediate
I2-d produces deuterated MTO, by the dissociation of
base. With an excess deuterium donor the reaction
sequence will be repeated until the three protons of
MTO are exchanged.
The rate constant difference between reactions with
phenol-d6 and o-cresol-d8 shows the absence of medium
effects, whereas the reaction with methanol-d4 implies
otherwise. The third-order rate constants measured
with D ) phenol-d6 and o-cresol-d8 in benzene-d6
represent the product K1K2k3. Because the K1K2 step is
common to both, the data reflect the relative values of
k3. The ratio of the rate constants with phenol-d6 and
o-cresol-d8 was 1.66, which roughly agrees with the Ka
ratio between phenol and o-cresol: Ka(phenol)/Ka(cresol)
) 1.99. Considering the use of aqueous pKa values and
In acetonitrile-d3, a noncoordinating polar solvent, the
deprotonated intermediate I2 can be stabilized by sol-
vation. This enolate-MTO facilitates the access to the
transition state and therefore lowers the activation
barrier for H/D exchange. Consequently, the formation
of I2 becomes the rate-determining step for B ) Lut, in
acetonitrile-d3 or in acetone-d6. On the other hand, a
weaker base cannot produce the reactive enolate-MTO;
(42) Popovych, O.; Tomkins, R. P. T. Nonaqueous Solution Chem-
istry; Wiley-Interscience: New York, 1981.
(43) Reichardt, C. Solvents and Solvent Effects in Organic Chemistry,
2nd ed.; VCH: Weinheim, Germany, 1988.