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the MP2 and M06-2X methods). The energy content of the re-
sulting four-membered iridacycles was very high, indicating
the highly strained nature of these compounds.[15] Therefore,
this hydrogenation pathway via the formation of such inter-
mediates derived from 3a was not further explored.[16] As
regards the hydrogenation pathway involving proton and
hydride transfers to the C=N bond of heterocyclic derivatives,
Crabtree and Eisenstein[14b] identified octahedral dihydrido
mono-dihydrogen iridium complexes as crucial intermediates
in the hydrogenation process. This is because hydrogen trans-
fer from H2 to the C=N bond starts with proton migration from
the dihydrogen ligand to the nitrogen atom. Once the C=N
bond is protonated,[17] the position alpha to nitrogen is activat-
ed for the subsequent hydride transfer, which is the stereo-
determining step (Scheme 2).
Our own studies[6a] and those of others[5b] have demonstrat-
ed that the complexation of P-OP ligands with [{Ir(m-Cl)(cod)}2]
quantitatively leads to compounds [Ir(Cl)(cod)(P-OP)], which
correspond to the expected neutral pentacoordinated irid-
ium(I) complexes. Removal of the cod ligand under hydrogena-
tive conditions led to a complex mixture of P-OP–iridium com-
plexes. Unfortunately, neither NMR nor X-ray analysis allowed
us to unequivocally establish the structure of the iridium com-
plexes present in solution (no crystals suitable for X-ray analy-
sis could be isolated from this mixture). For this reason, the rel-
ative stabilities of the plausible [Ir(Cl)(H)2(H–H)(L1 or L3)] com-
plexes were computed at the BP86/def2-SVP level of theory.
From among all the possible isomers in an octahedral iridium
complex with one bidentate (L1 or L3) and one chlorido
ligand, only those with the two hydrido and dihydrogen
ligands in a fac[18] (facial) geometry were considered.[19] This is
because hydrogen transfer from [Ir(Cl)(H)2(H–H)(L1 or L3)] com-
plexes will lead to a trihydrido iridium complex and metal tri-
hydrides have an intrinsic preference[14b] for a fac geometry to
avoid hydrido ligands that are mutually placed in a trans fash-
ion. Interestingly, in [Ir(Cl)(H)2(H–H)(L1)], the favorable fac iso-
mers (Figure 1) contain chlorido ligands pointing in the same
direction and perpendicular to the plane that contains the
P-OP and Ir atoms (Figure 1a, b). The slightly more favored
complex (by 0.3 kcalmolÀ1) has the H–H ligand cis to the phos-
phite group. With regard to [Ir(Cl)(H)2(H–H)(L3)], the lowest
energy isomers also contain chlorido ligands perpendicular to
the same plane but pointing in the opposite direction with re-
spect to the [Ir(Cl)(H)2(H–H)(L1)] complexes (Figure 1c, d). This
is due to the formation of intramolecular CÀH···Cl bonds (see
Figure 1 and Figure SI70 in the Supporting Information). This
differentiating feature is very important for rationalizing the
opposite enantioselectivity observed for L1 and L3 with
methyl substituted substrates such as 3a (see below).
Figure 1. a–d) Optimized geometries of the most stable isomers of
[Ir(Cl)(H)2(H–H)(L1 or L3)] (some H atoms are omitted for clarity; distances in
ꢂ; energies in kcalmolÀ1).
derstanding the stereochemical outcome of the reaction from
the protonated substrate (H3a). Beginning from the initial geo-
metry after proton transfer, where the NÀH group points to
the IrÀH motif (Figure 2a, b), we examined different orienta-
tions of the protonated substrate (H3a) interacting with
[Ir(Cl)(H)3(L1 or L3)]. Remarkably, we found a pre-TS complex
for each ligand (Figure 2c, d) that was lower in energy than
the initial assembly owing to the formation of favorable non-
covalent interactions. In the case of L1, the preferred arrange-
ment is governed by two interactions that fix the geometry of
the substrate [hydrogen-bonds (HB) and CH3···p interactions,
see Figure 2c]. This pre-organized complex facilitates the nu-
cleophilic attack of the hydrido group that is located 3.0 ꢂ
away from the C atom in the C=N group (pro-(S) attack). In the
case of L3, the presence of the chlorido ligand at the position
opposite the P-OP containing plane with respect to L1 and the
formation of a strong NÀH···Cl interaction fixes the substrate in
a different arrangement compared with L1. Moreover, the for-
mation of a CÀH···HÀIr noncovalent interaction[20] (Figure 2d)
fixes the position of the substrate, facilitating the pro-(R) attack
of the hydrido ligand (located at 3.1 ꢂ). The pre-TS complexes
that would organize the protonated substrate towards the
minor enantiomer (i.e., pro-(R) attack for L1 and pro-(S) attack
for L3) were not found on the potential hypersurface.
The geometries of the TSs are shown in Figure 3. It is impor-
tant to note the existence of strong NÀH···Cl hydrogen
bonds[21] in the favored TSs. These interactions are crucial in ra-
tionalizing the observed stereoselection. The difference in
energy between the two transition states derived from L1
(DDG# =2.2 kcalmolÀ1) is mainly governed by the different
strength of the two hydrogen-bond interactions: an NÀH···Cl
hydrogen-bond for the TS leading to the major enantiomer
(TSS; see Figure 3a) and an NÀH···O hydrogen-bond[22] for the
TS leading to the minor enantiomer (TSR; see Figure 3c). As
the NÀH···Cl interaction involves an anionic ligand, it is electro-
statically favored with respect to the NÀH···O interaction. As re-
gards L3, the transition state leading to the major enantiomer
Protonation of 3a by [Ir(Cl)(H)2(H–H)(L1 or L3)][17] leads to
the assembly of [H3a][Ir(Cl)(H)3(L1 or L3)] (Figure 2a, b). Both
isomers of complex [Ir(Cl)(H)2(H–H)(L1)] (Figure 1a, b) yield the
same fac trihydrido iridium complex upon proton transfer
(same behavior for L3), which simplifies the study. Proton
transfer is not the stereo-determining step and the configura-
tion of the final product is determined at the later stages of
the catalytic cycle. Therefore, we employed calculations for un-
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Chem. Eur. J. 2016, 22, 1 – 8
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