A. Krief, M. Derock / Tetrahedron Letters 43 (2002) 3083–3086
3085
(a)
(b)
[2 NaSeNa] + 2 H2
2 RSeR + 4 NaBr
2 Se + 4 NaH
[2 NaSeNa]
4 RBr
(e)
2 Se + 4 NaH + 4 RBr
2 Se + 4 NaH
2 RSeR + 4 NaBr + 2 H2
Scheme 5.
(a)
(b)
[NaSeSeNa + 2 NaH] + H2
4 RBr
[RSeSeR + 2 NaBr + 2 NaH + 2 RBr]
[NaSeSeNa + 2 NaH]
[RSeSeR + 2 NaH + 2 RBr]
[2 RSeNa + 2 RBr]
(c)
(d)
[2 RSeNa + 2 RBr] + H2
2 RSeR + 2 NaBr
(e)
2 Se + 4 NaH + 4 RBr
2 RSeR + 4 NaBr + 2 H2
Scheme 6.
(iv) alkylation of sodium alkylselenolates by the
unreacted alkyl halide (Scheme 6, step d).
sodium diselenide (61 ml [2.5 mmol] of dihydrogen
expected, Scheme 6, step a) and rules out the formation
of sodium selenide which would have instead produced
122 ml of dihydrogen (5 mmol, Scheme 5, step a).
In order to determine the real pathways (Scheme 5 or
Scheme 6 for example), we decided to monitor, by
volumetric titration, the amount of dihydrogen released
after addition of each reagent involved in the synthesis
of dialkyl selenides. For example, the amount of dihy-
drogen expelled prior to addition of any alkyl bromide
should be twice the amount, if Scheme 5 is operative, of
that expected if the reaction instead follows the path-
way disclosed in Scheme 6.
Addition, at that stage, of 2 mol equiv. (10 mmol) of
n-butyl bromide leads to the production of (i) 50 ml of
dihydrogen, (61 ml [2.5 mmol] expected, Scheme 6, step
c) and (ii) dibutyl selenide. These results unambiguously
support the sequence of reactions disclosed in Scheme
6.
Another support for this hypothesis arises from the
formation of dibutyl diselenide (94% yield) instead of
dibutyl selenide, when water is added prior to the
addition of n-butyl bromide (2 mol equiv.). This is due
to the destruction of the unreacted sodium hydride
which produces dihydrogen concomitantly (77 ml,
expected 61 ml, Scheme 8). Related results have been
obtained when propionic acid or aqueous hydrochloric
acid replaced water (dibutyldiselenide formed: 92%
yield, dihydrogen produced: 62 ml, expected 61 ml, in
each case).
Since some of the steps of this synthesis could be
identical to those implied in the related synthesis of
dialkyl diselenides (which only differs in that the Se/Na
ratio is 1/1 instead of 1/2, Scheme 7), we have, for
comparison purposes, monitored the amount of dihy-
drogen produced during the synthesis of dialkyl
diselenides.
We observed that the reaction between equivalent
amounts of selenium and sodium hydride (5 mmol
each) produces 58 ml of dihydrogen (61 ml [2.5 mmol]
of dihydrogen expected, Scheme 7, step a). This fully
agrees with the formation of sodium diselenide. Addi-
tion of 2 equiv. of n-butyl bromide provides dibutyl
diselenide (80% yield, Scheme 7, R=Bu) and as
expected no more dihydrogen is formed (Scheme 7, step
b).
We have used this information to propose a modified
and more appropriate experimental procedure to gener-
ate dialkyl selenides, which involves sequential addition
of each of the 2 equiv. of the alkyl halide [(i) elemental
selenium, 2 mol equiv. of NaH, DMF, 70°C, 2 h, (ii) 1
mol equiv. R1Br, 0°C, 0.2 h, (iii) 20°C, 2 h, (iv) 1 mol
equiv. R2Br 20°C, 6 h, conditions B, Scheme 2, Table
2]. These conditions significantly improve the yields in
symmetrical selenides (Table 2, compare conditions B
to conditions A).
It takes into account the observation that the two
alkyl groups present on the dialkyl selenide are not
delivered just one after the other as would have been
the case if sodium selenide was involved (compare
Scheme 6, steps b, d and Scheme 5).
Performing the reaction with twice the amount of
sodium hydride (10 mmol, Se/NaH ratio: 1/2), produces
69 ml of dihydrogen. This supports the formation of
(a)
[NaSeSeNa] + H2
RSeSeR + 2 NaBr
2 Se + 2 NaH
(b) [NaSeSeNa + 2 RBr]
It avoids the reaction between sodium hydride and
the second mol equiv. of the alkylating agent which
Scheme 7.